Problem 44958. Crop an Image

you should mention which is which in this matrix Icrop = crop_image(I, 2, 2, 1, 3)

Thank you Payam. I assume you meant specifying the order of the inputs explicitly. I have updated the description to make it clearer.

Good problem!

Can someone help me to solve this question? I did not learn image processing. So I tried to solve this question assuming that the pixels either have a value of 1 or 0. I am a beginner. This is my second day into coding. I would really love some help. This is my code:
[Ix,Iy]=size(I);
for n = 1:Ix %for Rmin
if I(n,:)==0
n = n + 1;
else n = n;
break
end
end
Rmin = n
for m = 1:Iy %for Cmin
if I(:,m)==0
m = m + 1;
else m = m;
break
end
end
Cmin = m
for o = Rmin:Ix %for Rmax
if I(o,Cmin) == 1
o = o+1;
elseif I(o,Cmin) == 0
o = o - 1;
break;
end
end
Rmax = o
for p = Cmin:Iy %for Cmax
if I(Rmin,p) == 1
p = p+1;
elseif I(Rmin,p) == 0
p = p - 1;
break;
end
end
Cmax = p

Rpix = Rmax - Rmin + 1
Cpix = Cmax - Cmin + 1

Hint please?

Hint 1: You need not know or use anything about the value of pixels in this image.
Hint 2: All you have to do is get a subset of a matrix in MATLAB (the matrix, in this case, represents an image).

The problem generates all the input values, so what is the reason I get a "Out of memory. The likely cause is an infinite recursion within the program." error when I simply input:

Icrop = crop_image(I, Rmin, Cmin, Rpix, Cpix)

I suggest to improve problem's statement.

I found I had to check my indices and subtract one.

I saw that image cropping function is frequently used in digital image processing

yea improve the statement

this is good concept for image processing

Difficult problem!

It took me time to do this

Very good conceptual problem about image.

(Rmin,Cmin) is the (x,y) coordinate of the image's left-top point, and Rpix*Cpix is the size of the rectangle image.

interesting problem

Good problem

Why doesn't this work?

Icrop = I(Rmin:Rmin+Rpix, Cmin:Cmin+Cpix)

I am a beginner, but this seems correct if I'm understanding the problem statement. Maybe I'm not..