Problem 60996. Dickson Polynomials
1st row of the output will be the coefficients of x, and, 2nd row of the output will be the coefficients of alpha.
When formulating the coefficitients of a variables, for terms where the other variable is present - consider the value of the other variable as 1. See examples below for a better understanding.
%Examplesa
n=2;
D2(x, alpha) = x^2 - 2*alpha
Output = [1 0 -2; 0 -2 1]
n=3;
D3(x, alpha) = x^3 - 3*x*alpha
Output = [1 0 -3 0; 0 0 -1 1]
n=5;
D5(x, alpha) = x^5 - 5*x^3*alpha + 5*x*alpha^2
% x (alpha=1) = 1*x^5 - 5*x^3*1 + 5*x*1^2 = [1 0 -5 0 5 0].*[x^5 x^4 x^3 x^2 x^1 x^0]
% alpha (x=1) = alpha^0*1^5 - 5*1^3*alpha^1 + 5*1*alpha^2
% = [0 0 0 5 -5 1].*[alpha^5 alpha^4 alpha^3 alpha^2 alpha^1 alpha^0]
Output = [1 0 -5 0 5 0; 0 0 0 5 -5 1]
Only vectorized solutions will be accepted. Check the test suite for banned functions.
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