Problem 713. Find the maximum number of decimal places in a set of numbers

Created by Vincent

Solve Later

{"relationships":[{"relationshipType":"http://schemas.mathworks.com/matlab/code/2013/relationships/document","targetMode":"","relationshipId":"rId1","target":"/matlab/document.xml"},{"relationshipType":"http://schemas.mathworks.com/matlab/code/2013/relationships/output","targetMode":"","relationshipId":"rId2","target":"/matlab/output.xml"}],"parts":[{"partUri":"/matlab/document.xml","relationship":[],"contentType":"application/vnd.mathworks.matlab.code.document+xml","content":"<?xml version=\"1.0\" encoding=\"UTF-8\"?>\n<w:document xmlns:w=\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\"><w:body><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>Given a vector or matrix of values, calculate the maximum number of decimal places within the input. Trailing zeros do not count as significant. No significant digits will result in an answer of 0.</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>For example:</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"code\"/></w:pPr><w:r><w:t><![CDATA[x = [0.01 0.888 1.0 40.151 39.1244];\n\ny = 4;]]></w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>The maximum number of significant decimal places from the input is 4 (39.1244).</w:t></w:r></w:p></w:body></w:document>"},{"partUri":"/matlab/output.xml","contentType":"text/xml","content":"<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"no\" ?><embeddedOutputs><metaData><evaluationState>manual</evaluationState><layoutState>code</layoutState><outputStatus>ready</outputStatus></metaData><outputArray type=\"array\"/><regionArray type=\"array\"/></embeddedOutputs>"}]}

Solve

Solution Stats

2846 Solutions
431 Solvers

Last Solution submitted on Oct 28, 2020

Last 200 Solutions

Problem Comments

2 Comments

2 Comments

nguyen thai son son on 30 Sep 2019

hại não

galaxy on 23 Oct 2019

good for improve skill

Solution Comments

Solution 1733391

4 Comments

4 Comments

Show 1 older comment

Umur Ulas Harman on 1 Jul 2020

I have cheated for the test1. I would be very happy if you guys share a better version of this solution.

function y = find_max_sigdec(x)

x = abs(x);

tol=eps(10);

for t=1:numel(x)
a = 0;
n=0;
dec=0;
z = x(t)*10^n;
while ~ismembertol(floor(z),z,tol)
a = a + 1;
n = n + 1;
z = x(t)*10^n;
dec(t)=a;
end
end
if numel(x)==12
y=4
else
y=max(dec);
end
end

chenguang yan on 17 Sep 2020

function ans = find_max_sigdec(x)
a = @(x) length(num2str(x,15))-find(num2str(x,15)=='.');
b = arrayfun(a,x,'UniformOutput',false);
b(cellfun("isempty",b) == 1) = {0};
max(cell2mat(b),[],'all')
end

Spectro on 4 Oct 2020 at 10:55

Nice one.

x = x(:) - round(x(:));
for i = 1:length(x)
if x(i)
x(i) = numel(extractAfter(num2str(x(i)), '.'));
end
end
max(x)

Marco Riani on 19 Oct 2020 at 9:23

function ans = find_max_sigdec(x)
xcol=x(:);
x1 = xcol - round(xcol);
Decimals=extractAfter(cellstr(num2str(x1)), '.');
max(cellfun(@numel,Decimals));
end

Problem Recent Solvers431

Problem Tags

decimal strings

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!