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Join Community Contest 2023: Unleash Your Creativity with MATLAB Animations!

Chen Lin 2023-10-31 （编辑时间：2023-11-27）

最新活动 由 Teodo 编辑于 2023-11-10

You are invited to join our 2023 community contest – MATLAB Flipbook Mini Hack! This year’s contest revolves around creating interesting animations using MATLAB.

Whether you are a seasoned MATLAB user or just getting started, this contest offers a fantastic opportunity to showcase your skills, learn from others, and engage with the vibrant MATLAB Central community.

Timeframe

This contest runs for 4 weeks from Nov. 6th to Dec. 3rd.

How to play

Create a new animation or remix an existing one with up to 2,000 characters of code.
Simply vote on the animations you love!

Prizes

You will have opportunities to win compelling prizes, including Amazon gift cards, MathWorks T-shirts, and virtual badges. We will give out both weekly prizes and grand prizes.

Check out the gallery and vote on the animations you like.

The MATLAB Central Community team

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8 个评论

Teodo 2023-11-10 （编辑时间：2023-11-10）

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Thank You, for this Great Contest, and for the (this year) freshness of propositions and rules. "Let the MATLAB games begin!" Cheers to all!

Adam Danz 2023-11-2

I'm glad to see some familiar names and faces in these comments who have participated in the previous mini hack contests! Invite your friends, colleagues, and classmates to join! I can't wait to see your 2-second, 48-frame animations!

Gregory Vernon 2023-11-2 （编辑时间：2023-11-2）

How will you count characters? Specifically

Are \n or \r considered characters?
Are end-of-line ; characters?
Are "clean-code" whitespaces a character? By these I mean indents on nested flow control, a = 1, etc.

Essentially, if someone submits code that looks like:

function c(v)
switch v
case 1
for a=1:10
b=a*2
disp(b)
end
case 2
for a=1:10
if mod(a,2)
b=a^2
else
b=a*2
end
disp(b)
end
end
end

Will that be counted as 112 characters? Or will it be reformatted to something like

function c( v )
    switch v
        case 1
            for a = 1 : 10
                b = a * 2;
                disp( b )
            end
        case 2
            for a = 1 : 10
                if mod( a, 2 )
                    b = a ^ 2;
                else
                    b = a * 2;
                end
                disp( b )
            end
    end
end