主要内容

本页采用了机器翻译。点击此处可查看最新英文版本。

检查或修改优化问题

使用 showwrite 检查问题

创建优化问题后,您可以使用 show 检查其表示。对于较大的问题,请改用 write。例如,

prob = optimproblem;
x = optimvar('x',2,'LowerBound',0);
prob.Objective = x(1) - 2*x(2);
prob.Constraints.cons1 = x(1) + 2*x(2) <= 4;
prob.Constraints.cons2 = -x(1) + x(2) <= 1;

show(prob)
  OptimizationProblem : 

	Solve for:
       x

	minimize :
       x(1) - 2*x(2)


	subject to cons1:
       x(1) + 2*x(2) <= 4

	subject to cons2:
       -x(1) + x(2) <= 1

	variable bounds:
       0 <= x(1)
       0 <= x(2)

此次检查展示了问题的基本要素,例如问题是求最小化还是最大化,以及变量边界。检查显示变量中使用的索引名称(如果有)。检查并未表明变量是否为整数值。

更改默认求解器或选项

为了尝试改进解或解速度,请检查并更改默认求解器或选项。

要查看默认求解器和选项,请使用 optimoptions(prob)。例如,

rng default
x = optimvar('x',3,'LowerBound',0);
expr = sum((rand(3,1).*x).^2);
prob = optimproblem('Objective',expr);
prob.Constraints.lincon = sum(sum(randn(size(x)).*x)) <= randn;
options = optimoptions(prob)
options = 

  lsqlin options:

   Options used by current Algorithm ('interior-point'):
   (Other available algorithms: 'trust-region-reflective')

   Set properties:
     No options set.

   Default properties:
              Algorithm: 'interior-point'
    ConstraintTolerance: 1.0000e-08
                Display: 'final'
           LinearSolver: 'auto'
          MaxIterations: 200
    OptimalityTolerance: 1.0000e-08
          StepTolerance: 1.0000e-12

   Show options not used by current Algorithm ('interior-point')

该问题的默认求解器是 lsqlin,您可以看到默认选项。

要更改求解器,请在 'Solver' 中设置 solve 名称-值对。要查看不同求解器适用的选项,请使用 optimoptions 将当前选项传递给不同的求解器。例如,继续这个问题,

options = optimoptions('quadprog',options)
options = 

  quadprog options:

   Options used by current Algorithm ('interior-point-convex'):
   (Other available algorithms: 'trust-region-reflective')

   Set properties:
    ConstraintTolerance: 1.0000e-08
          MaxIterations: 200
    OptimalityTolerance: 1.0000e-08
          StepTolerance: 1.0000e-12

   Default properties:
              Algorithm: 'interior-point-convex'
                Display: 'final'
           LinearSolver: 'auto'

   Show options not used by current Algorithm ('interior-point-convex')

要更改选项,请使用 optimoptions 或点符号来设置选项,并将选项传递给 solve 名称-值对中的 'Options'。请参阅常用的优化选项:调整和故障排除。继续这个示例,

options.Display = 'iter';
sol = solve(prob,'Options',options,'Solver','quadprog');
 Iter            Fval  Primal Infeas    Dual Infeas  Complementarity  
    0    1.500359e+00   3.068423e-01   2.275437e+00     2.500000e-01  
    1    1.728717e-01   0.000000e+00   7.719860e-03     3.637874e-02  
    2    2.604108e-02   0.000000e+00   0.000000e+00     5.245260e-03  
    3    7.822161e-03   0.000000e+00   2.775558e-17     1.407915e-03  
    4    2.909218e-03   0.000000e+00   6.938894e-18     2.070784e-04  
    5    1.931264e-03   0.000000e+00   1.734723e-18     2.907724e-05  
    6    1.797508e-03   0.000000e+00   2.602085e-18     4.083167e-06  
    7    1.775398e-03   0.000000e+00   4.336809e-19     5.102453e-07  
    8    1.772971e-03   0.000000e+00   2.632684e-19     3.064243e-08  
    9    1.772848e-03   0.000000e+00   5.228973e-19     4.371356e-11  

Minimum found that satisfies the constraints.

Optimization completed because the objective function is non-decreasing in 
feasible directions, to within the value of the optimality tolerance,
and constraints are satisfied to within the value of the constraint tolerance.

纠正错误指定的问题

要检查您的问题是否正确,请检查其所有方面。例如,通过运行此脚本创建一个优化问题来求解数独问题。

x = optimvar('x',9,9,9,'LowerBound',0,'UpperBound',1);
cons1 = sum(x,1) == 1;
cons2 = sum(x,2) == 1;
cons3 = sum(x,3) == 1;
prob = optimproblem;
prob.Constraints.cons1 = cons1;
prob.Constraints.cons2 = cons2;
prob.Constraints.cons3 = cons3;
mul = ones(1,1,9);
mul = cumsum(mul,3);
prob.Objective = sum(sum(sum(x,1),2).*mul);
cons4 = optimconstr(3,3,9);

for u = 1:3
    for v = 1:3
        arr = x(3*(u-1)+1:3*(u-1)+3,3*(v-1)+1:3*(v-1)+3,:);
        cons4(u,v,:) = sum(sum(arr,1),2) <= ones(1,1,9);
    end
end
prob.Constraints.cons4 = cons4;

B = [1,2,2;
1,5,3;
1,8,4;
2,1,6;
2,9,3;
3,3,4;
3,7,5;
4,4,8;
4,6,6;
5,1,8;
5,5,1;
5,9,6;
6,4,7;
6,6,5;
7,3,7;
7,7,6;
8,1,4;
8,9,8;
9,2,3;
9,5,4;
9,8,2];

for u = 1:size(B,1)
    x.LowerBound(B(u,1),B(u,1),B(u,1)) = 1;
end

该脚本有一些错误,您可以通过检查变量、目标和约束来发现这些错误。首先,检查变量 x

x
x = 

  9×9×9 OptimizationVariable array with properties:

 Array-wide properties:
          Name: 'x'
          Type: 'continuous'
    IndexNames: {{}  {}  {}}

 Elementwise properties:
    LowerBound: [9×9×9 double]
    UpperBound: [9×9×9 double]

See variables with show.
See bounds with showbounds.

该显示表明变量的类型是连续的。该变量应为整数值。更改类型。

x.Type = 'integer'
x = 

  9×9×9 OptimizationVariable array with properties:

 Array-wide properties:
          Name: 'x'
          Type: 'integer'
    IndexNames: {{}  {}  {}}

 Elementwise properties:
    LowerBound: [9×9×9 double]
    UpperBound: [9×9×9 double]

See variables with show.
See bounds with showbounds.

检查边界。应该有 21 个下界,值为 1,B 的每一行一个。因为 x 是一个大数组,所以将边界写入文件而不是在命令行上显示它们。

writebounds(x,'xbounds.txt')

在文件 xbounds.txt 中搜索 1 <= 的所有实例。在变量 x(1,1,1)x(2,2,2)、…、x(9,9,9) 中,只有 9 个下界的值为 1。为了调查这种差异,请检查设置下界的代码:

for u = 1:size(B,1)
    x.LowerBound(B(u,1),B(u,1),B(u,1)) = 1;
end

循环内的行应该说 x.LowerBound(B(u,1),B(u,2),B(u,3)) = 1;。将所有下界重置为零,然后运行更正后的代码。

x.LowerBound = 0;
for u = 1:size(B,1)
    x.LowerBound(B(u,1),B(u,2),B(u,3)) = 1;
end
writebounds(x,'xbounds.txt')

xbounds.txt 现在具有正确的下界数量,即 1。

检查目标函数。目标函数表达式很大,因此将表达式写入文件中。

write(prob.Objective,'objectivedescription.txt')
    x(1, 1, 1) + x(2, 1, 1) + x(3, 1, 1) + x(4, 1, 1) + x(5, 1, 1) + x(6, 1, 1) + x(7, 1, 1) + x(8,
    1, 1) + x(9, 1, 1) + x(1, 2, 1) + x(2, 2, 1) + x(3, 2, 1) + x(4, 2, 1) + x(5, 2, 1) + x(6, 2,
    ...
    9*x(7, 8, 9) + 9*x(8, 8, 9) + 9*x(9, 8, 9) + 9*x(1, 9, 9) + 9*x(2, 9, 9) + 9*x(3, 9, 9) +
    9*x(4, 9, 9) + 9*x(5, 9, 9) + 9*x(6, 9, 9) + 9*x(7, 9, 9) + 9*x(8, 9, 9) + 9*x(9, 9, 9)

目标函数看起来合理,因为它是标量表达式的总和。

将约束写入文件以供检查。

write(prob.Constraints.cons1,'cons1.txt')
write(prob.Constraints.cons2,'cons2.txt')
write(prob.Constraints.cons3,'cons3.txt')
write(prob.Constraints.cons4,'cons4.txt')

检查 cons4.txt,您会发现一个错误。所有的约束都是不等式而不是等式。更正创建此约束的代码行,并将更正后的约束放入问题中。

cons4 = optimconstr(3,3,9);

for u = 1:3
    for v = 1:3
        arr = x(3*(u-1)+1:3*(u-1)+3,3*(v-1)+1:3*(v-1)+3,:);
        cons4(u,v,:) = sum(sum(arr,1),2) == ones(1,1,9);
    end
end
prob.Constraints.cons4 = cons4;

经过这些改变之后,您就可以成功求解问题了。

sol = solve(prob);
x = round(sol.x);
y = ones(size(x));
for k = 2:9
    y(:,:,k) = k; % multiplier for each depth k
end
S = x.*y; % multiply each entry by its depth
S = sum(S,3); % S is 9-by-9 and holds the solved puzzle

drawSudoku(S)

变量名称重复

如果您重新创建一个变量,但已经有一个使用旧变量的表达式,那么在将表达式合并到单个问题中时可能会出现错误。请参阅变量名称不允许重复

另请参阅

| | | | | | |

主题