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cwtfreqbounds

CWT maximum and minimum frequency or period

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Syntax

[minfreq,maxfreq] = cwtfreqbounds(N)
[minfreq,maxfreq] = cwtfreqbounds(N,Fs)
[maxperiod,minperiod] = cwtfreqbounds(N,Ts)
[___] = cwtfreqbounds(___,Name=Value)

Description

[minfreq,maxfreq] = cwtfreqbounds(N) returns the minimum and maximum wavelet bandpass frequencies in cycles/sample for a signal of length N. The minimum and maximum frequencies are determined for the default Morse (3,60) wavelet. The minimum frequency is determined so that two time standard deviations of the default wavelet span the N-point signal at the coarsest scale. The maximum frequency is such that the highest frequency wavelet bandpass filter drops to ½ of its peak magnitude at the Nyquist frequency.

example

[minfreq,maxfreq] = cwtfreqbounds(N,Fs) returns the bandpass frequencies in hertz for the sampling frequency Fs.

[maxperiod,minperiod] = cwtfreqbounds(N,Ts) returns the bandpass periods for the sampling period Ts. maxperiod and minperiod are scalar durations with the same format as Ts. If the number of standard deviations is set so that log2(maxperiod/minperiod) < 1/NV where NV is the number of voices per octave, maxperiod is adjusted to minperiod × 2^(1/NV).

[___] = cwtfreqbounds(___,Name=Value) returns the minimum and maximum wavelet bandpass frequencies or periods with additional options specified by one or more Name=Value arguments. For example, [minf,maxf] = cwtfreqbounds(1000,TimeBandwidth=30) sets the time-bandwidth parameter of the default Morse wavelet to 30.

example

Examples

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Open Live Script

Obtain the minimum and maximum wavelet bandpass frequencies for a signal with 1000 samples using the default values.

[minfreq,maxfreq] = cwtfreqbounds(1000)
minfreq = 
0.0033

maxfreq = 
0.4341
Open Live Script

Obtain the minimum and maximum wavelet bandpass frequencies for the default Morse wavelet for a signal of length 10,000 and a sampling frequency of 1 kHz. Set the cutoff to 100% so that the highest frequency wavelet bandpass filter peaks at the Nyquist frequency of 500 Hz.

sigLength = 10000;
Fs = 1e3;
[minfreq,maxfreq] = cwtfreqbounds(sigLength,Fs,cutoff=100);

Construct a CWT filter bank using the values cwtfreqbounds returns. Obtain the frequency responses of the filter bank.

fb = cwtfilterbank(SignalLength=sigLength,SamplingFrequency=Fs,...
    FrequencyLimits=[minfreq maxfreq]);
[psidft,f] = freqz(fb);

Construct a second CWT filter bank identical to the first, but instead use the default frequency limits. Obtain the frequency responses of the second filter bank.

fb2 = cwtfilterbank(SignalLength=sigLength,SamplingFrequency=Fs);
[psidft2,~] = freqz(fb2);

For each filter bank, plot the frequency response of the filter with the highest center frequency. Confirm the frequency response from the first filter bank peaks at the Nyquist, and the frequency response from the second filter bank is 50% of the peak magnitude at the Nyquist.

plot(f,psidft(1,:))
hold on
plot(f,psidft2(1,:))
hold off
title("Frequency Responses")
xlabel("Frequency (Hz)")
ylabel("Magnitude")
legend("First Filter Bank","Second Filter Bank",...
    Location="NorthWest")

Figure contains an axes object. The axes object with title Frequency Responses, xlabel Frequency (Hz), ylabel Magnitude contains 2 objects of type line. These objects represent First Filter Bank, Second Filter Bank.

Open Live Script

Obtain the minimum and maximum frequencies for the bump wavelet for a signal of length 5,000 and a sampling frequency of 10 kHz. Specify a cutoff value of 100×10-8/2 so that the highest frequency wavelet bandpass filter decays to 10-8 at the Nyquist.

[minf,maxf] = cwtfreqbounds(5e3,1e4,wavelet="bump",cutoff=100*1e-8/2);

Construct the filter bank using the values returned by cwtfreqbounds. Plot the frequency responses.

fb = cwtfilterbank(SignalLength=5e3,Wavelet="bump",...
    SamplingFrequency=1e4,FrequencyLimits=[minf maxf]);
freqz(fb)

Figure contains an axes object. The axes object with title CWT Filter Bank, xlabel Frequency (kHz), ylabel Magnitude contains 80 objects of type line.

Open Live Script

Obtain the minimum and maximum wavelet bandpass frequencies for a signal of length 4096. Specify a cutoff of 0. Display the minimum and maximum bandpass frequencies.

sLength = 4096;
co = 0;
[minfreq,maxfreq] = cwtfreqbounds(sLength,Cutoff=co)
minfreq = 
8.0454e-04

maxfreq = 
0.1036

Create a filter bank using the frequency limits. Obtain the two-sided wavelet frequency responses. 

fb = cwtfilterbank(SignalLength=sLength, ...
    FrequencyLimits=[minfreq,maxfreq]);
[psif,f] = freqz(fb,FrequencyRange="twosided");

Obtain the minimum and maximum wavelet bandpass frequencies for a signal of length 4096, but this time specify a cutoff of 100×10-8/2. Create a second filter bank using these new frequencies. Confirm the second frequency range is larger than the first frequency range.

co = 100*(1e-8/2);
[minfreq2,maxfreq2] = cwtfreqbounds(sLength,Cutoff=co)
minfreq2 = 
8.0454e-04

maxfreq2 = 
0.2818

fb2 = cwtfilterbank(SignalLength=sLength, ...
    FrequencyLimits=[minfreq2,maxfreq2]);

Obtain the two-sided wavelet frequency responses of the second filter bank. 

[psif2,f2] = freqz(fb2,FrequencyRange="twosided");

Plot the frequency responses of the filter banks.

subplot(2,1,1)
plot(f,psif)
title("Frequency Responses: Zero Cutoff Filter Bank")
ylabel("Magnitude")
xlabel("Normalized Frequency (cycles/sample)")
subplot(2,1,2)
plot(f2,psif2)
title("Frequency Responses: Nonzero Cutoff Filter Bank")
ylabel("Magnitude")
xlabel("Normalized Frequency (cycles/sample)")

Figure contains 2 axes objects. Axes object 1 with title Frequency Responses: Zero Cutoff Filter Bank, xlabel Normalized Frequency (cycles/sample), ylabel Magnitude contains 71 objects of type line. Axes object 2 with title Frequency Responses: Nonzero Cutoff Filter Bank, xlabel Normalized Frequency (cycles/sample), ylabel Magnitude contains 85 objects of type line.

For the wavelet filter with the highest center frequency in each filter bank, obtain the magnitude of the frequency response at the Nyquist. Observer there is minimal difference between the two values.

fprintf("Zero Cutoff Filter Bank: %g", ...
    psif(1,floor(size(psif,2)/2)))
Zero Cutoff Filter Bank: 2.43333e-309

fprintf("Nonzero Cutoff Filter Bank: %g", ...
    psif2(1,floor(size(psif2,2)/2)))
Nonzero Cutoff Filter Bank: 1.02265e-08

Input Arguments

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Signal length, specified as a positive integer greater than or equal to 4.

Data Types: double

Sampling frequency in hertz, specified as a positive scalar.

Example: [minf,maxf] = cwtfreqbounds(2048,100)

Data Types: double

Sampling period, specified as a positive scalar duration.

Example: [minp,maxp] = cwtfreqbounds(2048,seconds(2))

Data Types: duration

Name-Value Arguments

Specify optional pairs of arguments as Name1=Value1,...,NameN=ValueN, where Name is the argument name and Value is the corresponding value. Name-value arguments must appear after other arguments, but the order of the pairs does not matter.

Example: [minf,maxf] = cwtfreqbounds(1000,Wavelet="bump",VoicesPerOctave=10) returns the minimum and maximum bandpass frequencies using the bump wavelet and 10 voices per octave for a signal with 1000 samples.

Before R2021a, use commas to separate each name and value, and enclose Name in quotes.

Example: [minf,maxf] = cwtfreqbounds(1000,"Wavelet","bump","VoicesPerOctave",10)

Analysis wavelet used to determine the minimum and maximum frequencies or periods, specified as "Morse", "amor", or "bump". These strings specify the analytic Morse, Morlet, and bump wavelet, respectively. The default wavelet is the analytic Morse (3,60) wavelet.

For Morse wavelets, you can also parametrize the wavelet using the TimeBandwidth or WaveletParameters name-value arguments.

Example: [minp,maxp] = cwtfreqbound(2048,seconds(1),Wavelet="bump")

Percentage of the peak magnitude at the Nyquist, specified as a scalar between 0 and 100. Setting Cutoff to 0 indicates that the wavelet frequency response decays to 0 at the Nyquist. Setting Cutoff to 100 indicates that the value of the wavelet bandpass filters peaks at the Nyquist.

For cwtfilterbank, the analytic wavelets filters peak at a value of 2. As a result, you can ensure the highest frequency wavelet decays to a value of α at the Nyquist frequency by setting Cutoff to 100 × α/2. In that case, you must have 0 ≤ α ≤ 2.

Note

Unless your application requires a strict cutoff value of 0, consider setting Cutoff to a small nonzero value, for example, on the order of 10-8. By specifying a small value, you can increase the frequency range [minfreq,maxfreq] and still obtain a wavelet frequency response that effectively decays to 0 at the Nyquist. See Frequency Range for Strictly Zero and Effectively Zero Cutoff Values.

Data Types: double

Number of time standard deviations used to determine the minimum frequency (longest scale), specified as a positive integer greater than or equal to 2. For the Morse, analytic Morlet, and bump wavelets, four standard deviations generally ensures that the wavelet decays to zero at the ends of the signal support. Incrementing StandardDeviations by multiples of 4, for example 4*M, ensures that M whole wavelets fit within the signal length. If the number of standard deviations is set so that log2(minfreq/maxfreq) > -1/NV, where NV is the number of voices per octave, minfreq is adjusted to maxfreq × 2^(-1/NV).

Data Types: double

Time-bandwidth for the Morse wavelet, specified as a positive scalar. The symmetry (gamma) of the Morse wavelet is assumed to be 3. The larger the time-bandwidth parameter, the more spread out the wavelet is in time and narrower the wavelet is in frequency. The standard deviation of the Morse wavelet in time is approximately sqrt(TimeBandwidth/2). The standard deviation in frequency is approximately 1/2*sqrt(2/TimeBandwidth).

If you specify TimeBandwidth, you cannot specify WaveletParameters.

Data Types: double

Morse wavelet parameters, specified as a two-element vector. The first element is the symmetry parameter (gamma), which must be greater than or equal to 1. The second element is the time-bandwidth parameter, which must be greater than or equal to gamma. The ratio of the time-bandwidth parameter to gamma cannot exceed 40.

When gamma is equal to 3, the Morse wavelet is perfectly symmetric in the frequency domain. The skewness is equal to 0. Values of gamma greater than 3 result in positive skewness, while values of gamma less than 3 result in negative skewness.

If you specify WaveletParameters, you cannot specify TimeBandwidth.

Data Types: double

Number of voices per octave to use in determining the necessary separation between the minimum and maximum scales, specified as an integer between 1 and 48. The minimum and maximum scales are equivalent to the minimum and maximum frequencies or maximum and minimum periods, respectively.

Data Types: double

Output Arguments

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Minimum wavelet bandpass frequency, returned as a scalar. minfreq is in cycles/sample if SamplingFrequency is not specified. Otherwise, minfreq is in hertz.

Data Types: double

Maximum wavelet bandpass frequency, returned as a scalar. maxfreq is in cycles/sample if SamplingFrequency is not specified. Otherwise, maxfreq is in hertz.

Data Types: double

Maximum wavelet bandpass period, returned as a scalar duration with the same format as Ts.

If the number of standard deviations is set so that log2(maxperiod/minperiod) < 1/NV, where NV is the number of voices per octave, maxperiod is adjusted to minperiod × 2^(1/NV).

Data Types: duration

Minimum wavelet bandpass period, returned as a scalar duration with the same format as Ts.

If the number of standard deviations is set so that log2(maxperiod/minperiod) < 1/NV, where NV is the number of voices per octave, maxperiod is adjusted to minperiod × 2^(1/NV)

Data Types: duration

Extended Capabilities

Version History

Introduced in R2018a

See Also

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