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Comma separated list generation

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Jan
Jan 2011-6-22
编辑： Stephen23 2024-2-22
How can you expand a comma separated list from a repetition? I am searching for the elegant way to do something like this:
Instead of
Y = blkdiag(X, X, X),
write Y = repblkdiag(X,3). The code I use now is:
function Y = repblkdiag(X, n)
Y = [];
for j = 1:n
Y = blkdiag(Y, X);
end
I expected that something like
Y = blkdiag(deal(repmat(X,3)))
would work. Thanks for your interest and contribution,
Jan

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采纳的回答

Andrei Bobrov
Andrei Bobrov 2011-6-22
xc = repmat({X},1,3)
Y = blkdiag(xc{:})
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Teja Muppirala
Teja Muppirala 2011-6-22
It is possible to do it in one line, but I think Andrei's solution is simpler.
Y = eval(['blkdiag( ' repmat('X,',1,3) '[])'])
Stephen23
Stephen23 2024-2-22
编辑：Stephen23 2024-2-22
Another neat approach:
C = {X};
Y = blkdiag(C{[1,1,1]})
One line (since R2019b):
Y = blkdiag(struct('x',repmat({X},1,3)).x)
... but I recommend using two lines.

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