Comma separated list generation

2 次查看（过去 30 天）
Jan
Jan 2011-6-22
编辑： Stephen23 2024-2-22
How can you expand a comma separated list from a repetition? I am searching for the elegant way to do something like this:
Instead of
Y = blkdiag(X, X, X),
write Y = repblkdiag(X,3). The code I use now is:
function Y = repblkdiag(X, n)
Y = [];
for j = 1:n
Y = blkdiag(Y, X);
end
I expected that something like
Y = blkdiag(deal(repmat(X,3)))
would work. Thanks for your interest and contribution,
Jan

请先登录，再回答此问题。

采纳的回答

Andrei Bobrov
Andrei Bobrov 2011-6-22
xc = repmat({X},1,3)
Y = blkdiag(xc{:})
  4 个评论
显示 2更早的评论
Teja Muppirala
Teja Muppirala 2011-6-22
It is possible to do it in one line, but I think Andrei's solution is simpler.
Y = eval(['blkdiag( ' repmat('X,',1,3) '[])'])
Stephen23
Stephen23 2024-2-22
编辑：Stephen23 2024-2-22
Another neat approach:
C = {X};
Y = blkdiag(C{[1,1,1]})
One line (since R2019b):
Y = blkdiag(struct('x',repmat({X},1,3)).x)
... but I recommend using two lines.

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Matrix Indexing 的更多信息

标签

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by