Why do I receive a segmentation violation when using the FFTN function?

2009 6 27

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If I run the following command at the MATLAB command prompt, I receive a segmentation violation:

X=rand(1000,3);
y=fftn(X, 1:100);

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This bug has been fixed in Release 14 Service Pack 3 (R14SP3). For previous product releases, read below for any possible workarounds:

This has been reported to our development team to be addressed in a future version of MATLAB.

A more correct approach for the above command would be the following:

X=rand(1000,3);
y = fftn(X,[1, 100]);

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