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Looping with indices that are not equally spaced

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John F
John F 2011-6-23
评论： Walter Roberson 2019-12-22
I'm trying to run a loop on a group of indices I obtained using "find". The indices will not always be consecutive. So, running a for loop like:
for i = indices
won't work. I'm trying to avoid doing something like:
for i = 1:length(VECTOR)
Any ideas?
  2 个评论
Oleg Komarov
Oleg Komarov 2011-6-23
not clear why it won't work. Depends how you structure the operations inside the loop. Post more code.
Daniel Shub
Daniel Shub 2011-6-23
What do you mean it doesn't work? What would you expect to get with:
indices = [1,2,3,5,7,13,11];
for i = indices, i, end

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采纳的回答

Laura Proctor
Laura Proctor 2011-6-23
Actually, it will work.
for idx = [ 1 -2 10 12.5 0 ]
disp(idx)
end
Isn't MATLAB cool?

更多回答（2 个）

John F
John F 2011-6-23
So, it works with a row vector of indices, but not a column?
I tried that bit of code but transposed idx, and the loop didn't work. Strange?
Frederick Abangba Akendola
Please, how do I write a “For” loop with irregular interval? For example; 2,4,8,16,32
  1 个评论
Walter Roberson
Walter Roberson 2019-12-22
for K = 2.^(1:5)
result = whatever involving K
end
However, most of the time you want to create one output per input. The general way to do that is
K_vals = 2.^(1:5);
numK = numel(K_vals);
results = zeros(size(K_vals));
for K_idx = 1 : numK
K = K_vals(K_idx);
results(K_id) = whatever involving K
end
plot(K_vals, results)

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