Why does this not work - Simple Matlab?

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Alex
Alex 2011-6-23
The following creates a matrix, then breaks it into lines, so that I can send each line as a vector to a function. I dont know if this is the best way, but it seems to work (Generally) However if any of the values in the matrix (array) are greater than 9, i.e double figures, it causes an error. Why? and what is there to fix it.
Thanks Guys
Alex
clear
array = [1,2,3;4,5,6;7,8,9]
openb=('[');
closeb = (']');
for ii = 1:length(array);
vv = sprintf('%s',num2str(array(ii,:)))
finalstring(ii,:) = strcat(openb,vv, closeb)
% finalnums(ii,:) = str2num(finalstring(ii,:));
% varargin{ii} = finalnums(ii,:);
end

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回答（1 个）

Walter Roberson
Walter Roberson 2011-6-23
That is definitely not a recommended way to proceed. Consider
output = arrayfun(@(K) YourFunction(array(K,:)), 1:size(A,1));
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Alex
Alex 2011-6-23
The function I want to use is call allcomb.
It requires the vectors sent to it like
allcomb([1 2], [34],[5 6])
Each of the vectors is a row in my matrix, however I dont always know the size of my originial matrix
Walter Roberson
Walter Roberson 2011-6-23
Your a has rows that are three columns wide, but what gets sent to your function has to be 2 columns wide per vector ?? Is it a single call to allcomb() with as many arguments as can be pulled out in pairs from A, or is it a limit or 3 pairs? If it is a limit of 3 pairs, then does the second call to allcomb "slide" the pairs over, e.g., allcomb([3 4],[5 6],[7 8]) ?
You have 11 values in the array; you cannot divide that up in to pairs without missing one of the values, not unless each one should slide by one, e.g., allcomb([2 3],[4 5],[6 7]) and so on until the end of the list ??

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