problem using matrix indexing with bsxfun.

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I'd like to calculate only A(a)*B(b), while keeping the original format of bsxfun(@times,A,B)
>> A=[-1 2 -3;4 -5 6;-7 8 -9];
B(:,:,1)=[-1 2 -3;4 -5 6;-7 8 -9];
B(:,:,2)=[-1 2 -3;4 -5 6;-7 8 -9];
bsxfun(@times,A,B)
ans(:,:,1) =
1 4 9
16 25 36
49 64 81
ans(:,:,2) =
1 4 9
16 25 36
49 64 81
>> a=A<0;b=B<0;
>> bsxfun(@times,A(a),B(b))
Error using bsxfun
Non-singleton dimensions of the two input arrays
must match each other.

采纳的回答

Matt J
Matt J 2013-10-31
编辑:Matt J 2013-10-31
I'd like to calculate only A(a)*B(b)
Have you checked what A(a) and B(b) look like? They are both vectors of different sizes so A(a)*B(b) has no clear definition,
>> A(a)
ans =
-1
-7
-5
-3
-9
>> B(b)
ans =
-1
-7
-5
-3
-9
-1
-7
-5
-3
-9
If you want all combinations of products A(a(i))*B(b(j)), you don't need bsxfun at all. It's just an outer product calculation,
A(a)*B(b).'
If this is not what you want, then you need to clarify what the final result should look like.
  3 个评论
Matt J
Matt J 2013-10-31
编辑:Matt J 2013-10-31
I assume you know for your specific data that such a multi-dimensional reshaping will always be possible. If you're sure it will be, then you can do
Aa=A(A<0);
Bb=reshape(B(B<0),[],1,size(B,3));
bsxfun(@times,Aa,Bb)

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