Function that will receive two function handles as input arguments and plot? - Homework

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Nora 2013-11-2

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回答： Iain 2013-11-4

So I am working on this problem:

Write a function that will receive two function handles as input arguments adn will display plots of these functions in two subplots(column-wise) in a single figure window. The function will create an x vector that has 100 random numbers from 1 to 100.
example: if the function is called plot2fnhand
plot2fnhand(@sqrt,@exp)
the first subplot would display the sqrt function, the second would display exp(x) function.

This is what I have for my function so far:

function rfh = plot2fnhand( x, fh1, fh2 )
x = rand(100);
subpot(2,1,1);
y = fh1(x);
plot(x,y);
title(func2str(fh1));
subpot(2,1,2);
y = fh2(x);
plot(x,y);
title(func2str(fh2));
rfh = @testhd;
end
function testhd()
disp('HANDLE PASSING');
end

I keep on getting errors. ????

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Nora 2013-11-2

Item one
Item two

I am calling this function like the example above:

plot2fnhand(@sqrt,@exp)

x variable will be a random number between 1 to 100. and so then the two inputs will be plotted based on that.

I am confused on how to approach this problem.

I took out the second plot for both of them but it still doesn't allow me to plot them.

function plot2fnhand( fh1, fh2 )

x = rand(100); %\\ subplot(2,1,1);

y = fh1(x);

plot(x,y);

title(func2str(fh1));

subplot(2,1,1);

y = fh2(x);

plot(x,y);

title(func2str(fh2));

end

I get this error message:

EDU>> plot2fnhand(@sin,@cos)

Undefined function or variable 'Q1'.

Error in plot2fnhand (line 18)

y = fh2(x);Q1

???

Image Analyst 2013-11-2

Did you overlook this in my answer: <http://www.mathworks.com/matlabcentral/answers/13205-tutorial-how-to-format-your-question-with-markup???

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Answer 1

Iain 2013-11-4

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链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/104702-function-that-will-receive-two-function-handles-as-input-arguments-and-plot-homework#answer_114068

在 MATLAB Online 中打开

"Undefined function or variable 'Q1'."

Looks like you have referred to Q1 without meaning to.

A function containing

 function whatever
 a = 1; b = 2; c = 3; disp(c); d
 end

will throw a similar error because "d" is interpreted as code.

A function containing

 function whatever
 a = 1; b = 2; c = 3; disp(c); % d
 end

will not throw a similar error because "%" tells matlab to ignore everything, following it on the same line.

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