Error using arrayfun : Non scalar in Uniform output

2013 11 5
1 个回答
更新时间：2013 11 5
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0 个投票

Hello,
I have a cell array (Z) of size (480*1) where in each row I have the individual double arrays that I want(e.g. 1*70 double). Now I want to apply a custom function to each row (each elements of the cell), for this I use arrayfun:
C = arrayfun(@ (x) (((a/length(Z))*(1/(2*pi))).*((abs(fftshift(fft(Z,1024))).^2))),1:480);
and I get this error:
Error using arrayfun Non-scalar in Uniform output, at index 1, output 1. Set 'UniformOutput' to false.
(Worth mentioning that I zeropad my fft, so the output data are all the same size(1*1024))

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回答（1 个）

Azzi Abdelmalek
Azzi Abdelmalek 2013-11-5
编辑：Azzi Abdelmalek 2013-11-5

2 个投票

Add 'uniformoutput',false or 'un',0
C = arrayfun(@ (x) (((a/length(Z))*(1/(2*pi))).*((abs(fftshift(fft(Z,1024))).^2))),1:480,'un',0);

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Thanks for your answer, but it shouldn't be the problem of output size since all outputs do to use of zeropadding must be of size 1*1024. With your correction the error will be:
Undefined function 'fft' for input arguments of type 'cell'.
Error in @(x)(((a/length(Z))*(1/(2*pi))).*((abs(fftshift(fft(Z,1024))).^2)))
Azzi Abdelmalek
Azzi Abdelmalek 2013-11-5
编辑：Azzi Abdelmalek 2013-11-5
Change fft(Z,1024) by fft(x,1024)
C = arrayfun(@ (x) (((a/length(Z))*(1/(2*pi))).*((abs(fftshift(fft(x,1024))).^2))),1:480,'un',0);
x in your expression is 1:480, while fft is going to be applied on each element of Z(as explained in my question) i.e. Z{1} which has 1*70 elements , then Z{2} having 1*58 elements,...
Azzi Abdelmalek
Azzi Abdelmalek 2013-11-5
Ok, then use cellfun
C = cellfun(@ (x) (((a/length(Z))*(1/(2*pi))).*((abs(fftshift(fft(x,1024))).^2))),Z,'uniformoutput',false);

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