what am I doing wrong?

I have a doubt in the representation of a discrete signal. With help from Azzi Abdelmalek I wrote the following code
p=-5:0.0001:5;
%Input number
Imp=input('number pulse:\n');
out=zeros(1,numel(p));
for x = 1:Imp
%input amplification
a(x)=input('amplification pulse:\n');
%step position
p(x)=input('initial Position:\n');
out=out+a(x)*heaviside(p-p(x));
stem(p,out);
end
xlabel('Position');
ylabel('Amplification');
title('graph');
grid on;
but the representation is wrong,what am I doing wrong?
The signal must be a sum of impulses and the user to choose the number of pulses and each pulse amplitude and choose your position, as follows: x (n) = a1  (n-n1) a2 +  (n-n2) + ...

回答(2 个)

Walter Roberson
Walter Roberson 2013-11-6

0 个投票

You are using p to represent the locations being sampled at, and you are using p(x) to represent the pulse positions, but p(x) is the same vector as vector p . You should be using two different names for the two different items.

3 个评论

the problem is the same
Please update your code with the variables that have the new names that Walter suggested. You said you made the changes he suggested, but we don't want to make recommendations on code we haven't seen.
if true
p=-5:0.0001:5;
%Input number
Imp=input('number pulse:\n');
out=zeros(1,numel(p));
for x = 1:Imp
%input amplification
a(x)=input('amplification pulse:\n');
%step position
p1(x)=input('initial Position:\n');
out=out+a(x)*heaviside(p-p1(x));
stem(p,out);
end
xlabel('Position');
ylabel('Amplification');
title('graph');
grid on;
end

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Manuel
Manuel 2013-11-7

0 个投票

I do not understand what I'm doing wrong

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提问:

2013-11-6

回答:

2013-11-7

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