Error using cos Not enough input arguments. HELP

2013 11 6
3 个回答
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更新时间：2021 6 29
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Hi all,
Can anyone help me with this problem - Error using cos Not enough input arguments.
x=0:0.25:5.*pi;
y=0:0.25:2.*pi;
[x,y]=meshgrid(x,y);
z = cos.*((x).*sin(y)).*((1-3.*cos((y).^2))-(x.^2).*sin((y).^2)).*cos(x);
Error using cos Not enough input arguments.
I'm new to MatLab and I need to plot a contour map using this function but I can't seem to find a way to get rid of the error message. Any help would be much appreciated.
Thanks, Kayn.

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 采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2013-11-6
编辑：Azzi Abdelmalek 2013-11-6

1 个投票

You missed something in cos.* ,maybe you want
z = cos(x).*((x).*sin(y)).*((1-3.*cos((y).^2))-(x.^2).*sin((y).^2)).*cos(x);
You missed something in cos.

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Gnaneswar Nadh satapathi
编辑：Azzi Abdelmalek 2013-11-6
clc
clear all
close all
x=0:0.25:5.*pi;
y=0:0.25:2.*pi;
[x,y]=meshgrid(x,y);
z = (cos(x).*sin(y)).*((1-3.*cos((y).^2))-(x.^2).*sin((y).^2)).*cos(x);
contour(x,y,z)
Kayn
Kayn 2013-11-6
Hi Azzi, Thanks for the reply. Although your solution removes the error it changes the equation. It has however highlighted the area where the error is occurring. I basically need the code then for this part of the function - cos(xsin(y))
Your answer gives (cos(x))(xsin(y)) which although removes the error, it doesn't give the correct equation describing the energy interaction I'm working on.
So, does anyone know how to write cos(xsin(y)) in MatLab syntax? I figured it would be cos(x.*sin(y)) or cos.*(x.*sin(y)) but both give the error code.
Cheers
Kayn
Kayn 2013-11-6
Yes, this works! Many, many thanks Azzi. I now have my contour maps and am trying to make them look nice. Thanks again.

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更多回答（2 个）

0 个投票

diff(sin^2*([cos^2*(x^2)]))
Error using sin
Not enough input arguments.
help.

1 个评论
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Walter Roberson
Walter Roberson 2021-3-6
Ran in:
Ran in:
syms x
diff(sin(x)^2 * cos(x^2)^2, x)
ans = 
or possibly you meant
syms x
diff(sin(cos(x^2)^2)^2, x)
ans = 

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5*cos(x)+4.2501-cos*(0.52367-x)
Error using cos
Not enough input arguments.
Error in Secant2 (line 13)

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Walter Roberson
Walter Roberson 2021-6-29
You have a function named Secant2 that takes at least one parameter, that is named x in the function.
When you ran the function Secant2 you did not provide any parameters at the time of the call. You probably just pressed the big green Run button. When you press the green Run button, MATLAB will run the function without providing any parameters. If you run a function that has a variable (such as x) defined as a parameter, but you run the function without providing a value in that position, then MATLAB will never go hunting around elsewhere looking for an "x" defined somewhere to use as the value in the function. For example,
x = pi/7
y = sin
if sin were defined like
function sx = sin(x)
then MATLAB will never go looking in the workspace to find the pi/7 value to use for the function. If you want a function to use a parameter, then you have to pass the parameter to it.

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