Binding Energy per nucleon vs A Plot
显示 更早的评论
a1=14.1; a2=13.0; a3=0.595; a4=19.0; a5=33.5; A=2:300; Z=(1/2).*A./(1+A.*(2/3)*(a3/4*a4)); b=mod(Z,2); c= mod(A,2); if b==c if c==0 BE=a1-(a2./A.^(1/3))-(a3.*Z.^2./A.^(4/3))-(a4.*((A-(2.*Z)).^2)./A.^2)+(a5./A.^(7/4)); elseif b==1 BE=a1-(a2./A.^(1/3))-(a3.*Z.^2./A.^(4/3))-(a4.*((A-(2.*Z)).^2)./A.^2)-(a5./A.^(7/4)); end
else BE=a1-(a2./A.^(1/3))-(a3.*Z.^2./A.^(4/3))-(a4.*((A-(2.*Z)).^2)./A.^2); end plot(A,BE)
This is the plot written by me to plot Binding energy Per nucleon vs A ,Don't know why but the plot made by this code is very much different from the real plot ,So cn u plz tell me where I have done mistake ? thnx
回答(0 个)
类别
在 帮助中心 和 File Exchange 中查找有关 MATLAB 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!