how can plot error with number of iteration?

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Mary Jon
Mary Jon 2013-11-14
评论： Azzi Abdelmalek 2013-11-15
when used (while loop) as stopping condition of process ,we specified the value of error may be 0.001 or 0.00001
if I have number of iteration ,How can plot the error with iteration numbers?
  2 个评论
Mary Jon
Mary Jon 2013-11-14
if I have 120 iteration ,how can plot its
this code of error ,
[i j]=ndgrid(1:111,1:33);
G=(sum(sum((abs(v_now-v_prev)))));
MPD=G/(m*n); %error stoping criteria
while(MPD>0.00001); %Run this until convergence

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回答（1 个）

Azzi Abdelmalek
Azzi Abdelmalek 2013-11-14
[i j]=ndgrid(1:111,1:33);
MPD=1;
while(MPD>0.00001);
G=(sum(sum((abs(v_now-v_prev)))));
MPD=G/(m*n);
% your code
end
  8 个评论
显示 6更早的评论
Mary Jon
Mary Jon 2013-11-15
iter=0;
[i j]=ndgrid(1:111,1:33);
MPD=1;
G=(sum(sum((abs(v_now-v_prev)))));
MPD=G/(m*n); %error stoping criteria
while(MPD>0.00001); %Run this until convergence
iter=iter+1; % Iteration counter increment
hold on
plot(MPD,iter)
end
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%end of code %%%%%%%%%%%%
Azzi Abdelmalek
Azzi Abdelmalek 2013-11-15
You are not doing anything inside the loop. Try
iter=0;
MPD=1;
while(MPD>0.00001); %Run this until convergence
G=(sum(sum((abs(v_now-v_prev)))));
MPD=G/(m*n); %error stoping criteria
iter=iter+1; % Iteration counter increment
hold on
plot(iter,MPD)
end

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