How can I plot multiple signals with unit step signal

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I need to plot this function:
v(t)=(2t+1)[u(t)-u(t-1)]+3[u(t-1)-u(t-2)]+(-t+3)[u(t-2)-u(t-3)]

采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2013-11-15
t=-5:0.1:5
v=(2*t+1).*(heaviside(t)-heaviside(t-1))+3*(heaviside(t-1)-heaviside(t-2))+(-t+3).*(heaviside(t-2)-heaviside(t-3))
plot(t,v,'linewidth',4)

更多回答(1 个)

Wayne King
Wayne King 2013-11-15
编辑:Wayne King 2013-11-15
Looks to me like this just simplifies to:
\delta(t) +3\delta(t-1) + \delta(t-2)
N = 128;
sig = zeros(N,1);
idx = 1:3;
sig(idx) = [1 3 1];
stem(sig)
u(t)-u(t-1) is like the derivative of the unit step at t, which is the delta function (distribution)
You can see it's equal if you implement your equation above using the differences of the translated unit step functions:
stepfunc = ones(128,4);
stepfunc(1,2) = 0;
stepfunc(1:2,3) = 0;
stepfunc(1:3,4) = 0;
t = (0:127)';
v1 = 2*t+1;
v2 = -t+3;
v = v1.*(stepfunc(:,1)-stepfunc(:,2))+ 3*(stepfunc(:,2)-stepfunc(:,3))+...
v2.*(stepfunc(:,3)-stepfunc(:,4));
subplot(211)
stem(v)
subplot(212)
stem(sig)

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