how do you write a conditional struct?

2013 11 18
2 个回答
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更新时间：2013 11 18
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Walter Roberson
Walter Roberson 2013-11-18

1 个投票

At the beginning start with
data = [];
Then, in each of the error cases, after you disp() the string, add
return
before the "end" of the "if"
if condition
disp('message')
return
end

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Azzi Abdelmalek
Azzi Abdelmalek 2013-11-18

0 个投票

Maybe you are asking about if/elseif/else

4 个评论
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vishant m.
vishant m. 2013-11-18
i tried using if, but it doesnt work :( can you give a simple example
Matt J
Matt J 2013-11-18
编辑：Matt J 2013-11-18
@vishant
Why don't you give an example of what doesn't work and describe what you want to happen instead.
vishant m.
vishant m. 2013-11-18
编辑：Azzi Abdelmalek 2013-11-18
function data=test3(n)
if isnumeric(n)==0;
n=([1 2 3 4]); display('input has two many terms or is not a vector');
end
if isvector(n)==0;
n=([1 2 3 4]); display('input has two many terms or is not a vectorl');
end
x=linspace(-5,5,1000);
y=polyval(n,x);
plot(x,y);
q=roots(n);
data=plot(q(imag(q)==0), zeros(sum(imag(q)==0)),'r+');
data= struct('x',x,'p',n,'rp',q,'rpp',q(imag(q)==0),'px',(x));
end
this is the code, you can see the struct. there are 2 if functions at the start, i need the struct to give ans[] when the condition of any of the ifs applies.
Azzi Abdelmalek
Azzi Abdelmalek 2013-11-18
[i need the struct to give ans[] when the condition of any of the ifs applies.] I can't understand what you mean

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