perl script to matlab code conversion

shobi swaminathan

2013 11 19

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the following is the program that was converted from perl version to matlab. when executed in perl i got "pa" value around 9.81..but in matlab iam getting only 0.0763..can someone tel me y?..i need this answer badly pls

clc;
clear all;
j=1:6;
for i=0:length(j) 
    beta=2^i;
    alow=0;
    ahigh=10000;
    pa=0;
    r=3;
    eps=0.1;
    gminus=0;
    gplus=0;
    g=0;
    fa=0;
    while((ahigh-alow)>eps)
        pa=(alow+ahigh)/2;
        fa=1-(exp(-((((2^r)-1)/pa)^(beta/2))));
        gminus=(((fa-1)/pa)*(pa-eps))+1;
        glus=(((fa-1)/pa)*(pa+eps))+1;
        fminus=1-(exp(-((((2^r)-1)/(pa-eps))^(beta/2))));
        fplus=1-(exp(-((((2^r)-1)/(pa+eps))^(beta/2))));
        if(((gminus<fminus)&&(gplus>fplus))==1)
            alow=pa;
        else
         ahigh=pa;
      end
         disp(pa)  
    end

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Simon 2013-11-19

Hi!

It's not so easy to tell where the difference comes from if we only know the matlab code and not the perl code.

BTW, your code is missing an "end" at the end.

Walter Roberson 2013-11-19

The poster has indicated that this code was executed in perl. Which is not plausible, as perl requires $ or @ before each variable name (except sometimes for file handles.)

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