perl script to matlab code conversion
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the following is the program that was converted from perl version to matlab. when executed in perl i got "pa" value around 9.81..but in matlab iam getting only 0.0763..can someone tel me y?..i need this answer badly pls
clc;
clear all;
j=1:6;
for i=0:length(j)
beta=2^i;
alow=0;
ahigh=10000;
pa=0;
r=3;
eps=0.1;
gminus=0;
gplus=0;
g=0;
fa=0;
while((ahigh-alow)>eps)
pa=(alow+ahigh)/2;
fa=1-(exp(-((((2^r)-1)/pa)^(beta/2))));
gminus=(((fa-1)/pa)*(pa-eps))+1;
glus=(((fa-1)/pa)*(pa+eps))+1;
fminus=1-(exp(-((((2^r)-1)/(pa-eps))^(beta/2))));
fplus=1-(exp(-((((2^r)-1)/(pa+eps))^(beta/2))));
if(((gminus<fminus)&&(gplus>fplus))==1)
alow=pa;
else
ahigh=pa;
end
disp(pa)
end
4 个评论
Simon
2013-11-19
Hi!
It's not so easy to tell where the difference comes from if we only know the matlab code and not the perl code.
BTW, your code is missing an "end" at the end.
Walter Roberson
2013-11-19
The poster has indicated that this code was executed in perl. Which is not plausible, as perl requires $ or @ before each variable name (except sometimes for file handles.)
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