how do I delete values from a matrix when my loop condition is false?

2 次查看（过去 30 天）
ilona
ilona 2013-11-23
回答： Jan 2013-11-23
I encountered a problem - my intention was to delete values in the matrix in certain conditions - the problem is that when I define my loop to delete item from my matrix in certain conditions when the loop keep going I get this message: >> Index of element to remove exceeds matrix dimensions. does someone has an idea to resolve my problem?
this is the important part of my code:
%
unitVec = round(0+(5).*rand(1,50));
bagUpVec = bagVec;
for jj = 1:size(bagVec,2);
if unitVec(jj)== 5;
bagUpVec(jj) == bagVec(jj)+10;
end
end
%
psychPass = zeros(1,50);
unitPass = zeros(1,50);
unitWait = zeros(1,50);
numReject = 0;
numPass = 0;
for jj = 1:size(bagUpVec,2);
if (bagUpVec(jj) >= 90) && (psychVec(jj)>= 700)
psychPass(jj) = psychVec(jj);
unitPass(jj) = unitVec(jj);
numPass = numPass + 1;
unitWait(jj)=[];
elseif (bagUpVec(jj) < 85) ...
&& (psychVec(jj)< 600)
numReject = numReject + 1;
unitWait(jj) = [];
else
psychPass(jj) = [];
unitPass(jj) = [];
unitWait (jj) = unitVec(jj);
end
end

请先登录，再回答此问题。

回答（1 个）

Jan
Jan 2013-11-23
Some hints:
unitVec = round(5 .* rand(1, 50));
bagUpVec = bagVec; % ??? What is "bagVec"?
index = (unitVec == 5);
bagUpVec(index) = bagUpVec(index) + 10;
Ich you delete unitWait(k), the higher elements are moved to the front, such that the former last element moves one index to the front:
a = [1,2,3]
a(1) = [] % a = [2, 3] !!
a(3) = [] % error !
A better method:
index = [1,3];
a(index) = [];

类别

在 Help Center 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by