For loop repetition question
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Hey guys, I'm trying to make my code below to give me N=1:10 (repeating the for loop 10 times) in addition to 1:20 and 1:50, do I need to make separate for loops for this or is there some way to get the current loop to give me this information?
clear;
x0=[42;0;95];
extinct=0;
W=zeros(1,200);
for N=[1:10]
F=2*rand(1)
for t=1:200;
W(t)=F;
A=[0 0 F; .6 0 0; 0 .75 .55];
x=(A^t)*x0;
if (sum(x)<1);
extinct=extinct+1;
break;
end
end
end
fprintf('Number of extinction events:%d\n',extinct)
采纳的回答
Image Analyst
2013-11-29
You don't need the brackets, by the way. You'd need to wrap that whole loop in another loop to handle the other top values of N:
upperN = [10,20,50]
for k = upperN
fprintf('Upper N = %d\n', k);
for n = 1 : k
fprintf(' n = %d\n', n);
end
end
更多回答（1 个）
Roger Stafford
2013-11-29
0 个投票
Are you certain you want matrix power in A^t rather than element-wise power as in A.^t? Either way, your coding can be made more efficient in my opinion. Also what is the point of W(t) here. It gets repeatedly erased in subsequent passes through the outer loop - that is, for each subsequent value of N the array W is overwritten, or at least partially so.
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