issue in matrix multiplication

2 次查看（过去 30 天）
mary
mary 2013-12-4
回答： Walter Roberson 2013-12-5
G=[1 1 1 1 1 0 0 0 1 0 0 0; 0 0 1 1 0 0 0 1 0 1 0 0; 1 1 1 0 1 0 0 1 0 0 1 0; 1 0 0 1 1 1 0 1 0 0 0 1];
m=[1 0 1 0]
how to multiply them??

请先登录，再回答此问题。

采纳的回答

Youssef Khmou
Youssef Khmou 2013-12-4
编辑：Youssef Khmou 2013-12-4
G is 4x12 and m is 1x4, then two possibilities :
m*G
G'*m'
You do not get binary result because of the multiplication cij=sum a_ik b_kj there is an addition. you can get binary results if the matrices have the same dimensions and you use Hadamard product :
m=m'
M=zeros(4,12);
for n=1:12
M(:,n)=m;
end
M.*G

更多回答（4 个）

Wayne King
Wayne King 2013-12-4
编辑：Wayne King 2013-12-4
G=[1 1 1 1 1 0 0 0 1 0 0 0; 0 0 1 1 0 0 0 1 0 1 0 0; 1 1 1 0 1 0 0 1 0 0 1 0; 1 0 0 1 1 1 0 1 0 0 0 1];
m=[1 0 1 0];
out = m*G;
How else would you presume to multiply them?
  1 个评论
mary
mary 2013-12-4
when i multiplied them using this way the result will be [ 2 2 3 2 2 0 0 2 1 1 1 0]

请先登录，再进行评论。

Walter Roberson
Walter Roberson 2013-12-4
G is 12 x 4, and m is 1 x 4, so there is no direct way to multiply them. You can, however, use
G * m.'
to get 12 x 1, or you can use
m * G.'
to get 1 x 12
Possibly what you want is
G .* repmat(m.', 1, size(G,2))
  1 个评论
mary
mary 2013-12-4
G is 4 by 12 if i multiply them directly the result is not binary ?? how come??

请先登录，再进行评论。

sixwwwwww
sixwwwwww 2013-12-4
mary you can get desired output as follows:
G = [1 1 1 1 1 0 0 0 1 0 0 0; 0 0 1 1 0 0 0 1 0 1 0 0; 1 1 1 0 1 0 0 1 0 0 1 0; 1 0 0 1 1 1 0 1 0 0 0 1]';
m = [1 0 1 0];
idx = find(m);
result = zeros(1, size(G, 1));
for i = 1:size(G, 1)
result(i) = sum(G(i, min(idx):max(idx)));
end
disp(result)
Do you need this?
  1 个评论
mary
mary 2013-12-4
not this i need the result in binary .. just multiplying two matrices and the result would be binary

请先登录，再进行评论。

Walter Roberson
Walter Roberson 2013-12-5

类别

在 Help Center 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by