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Identifying sequences of two or more and maintaining vector shape

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MohammedLee Lee
MohammedLee Lee 2013-12-6
编辑： Andrei Bobrov 2013-12-6
I'm pretty new to Matlab and know what I want to do, just not how to code it. I have a vector in which I want to remove nonzero values which are not in a sequence of two or more i.e.
0 112 58 0 0 0 0 114 0 24 0 0
and turn the 114 and 24 values to 0, but keep any value sequences of two or more.
I've switched to logicals to keep things simple and managed to find out how many times there are these sequences:
ML4= find(diff([-1 ML3 -1]) ~= 0);
runlength = diff(ML4) ;
runlength1 = runlength(1+(ML3(1)==0):2:end);
numberBursts=sum(runlength1>1);
but not a way to keep the original vector shape Any help much appreciated.

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采纳的回答

Andrei Bobrov
Andrei Bobrov 2013-12-6
编辑：Andrei Bobrov 2013-12-6
x = [0 112 58 0 0 0 0 114 0 24 0 0];
x(strfind([0,x(:)' ~= 0, 0],[0 1 0])) = 0;

更多回答（1 个）

Jos (10584)
Jos (10584) 2013-12-6
x = [0 112 58 0 0 0 0 114 0 24 0 0]
xx = [false x~=0 false]
ix = 2:numel(x)+1
tf = ~xx(ix-1) & xx(ix) & ~xx(ix+1)
y = x
y(tf) = 0

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