How to find position of something

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Martina
Martina 2013-12-7
回答： Roger Stafford 2013-12-7
Hi, I am having a problem with part of my homework. I have a column with numbers and NaN-s. If I have 5 or more NaN-s in a row I need to know place/position where NaN start (j) and end (i) ( in all column). For example 7 6 5 NaN NaN NaN NaN NaN NaN 9 7
j=4 i=9 Thanks you very much :)

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Roger Stafford
Roger Stafford 2013-12-7
You can use the 'find' and 'diff' functions as well as 'isnan' to accomplish that. Let A be your column vector of elements with possible NaNs among them.
m = 5; % The minimum length of consecutive NaNs to record
f = find(diff([false;isnan(A);false]));
B = [f(1:2:end-1),f(2:2:end)-1]; % Get all start and end indices for NaN consecutive sequences
B = B(B(:,2)-B(:,1)+1>=m,:); % Eliminate all with fewer than m NaNs
The first column of array B contains the start indices and the second column the end indices for consecutive sequences of at least five NaNs.

更多回答（2 个）

Mohammad Monfared
Mohammad Monfared 2013-12-7
Suppose you have a column or row vector named 'A',
find(isnan(A))
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Mohammad Monfared
Mohammad Monfared 2013-12-7
It's not a straightforward simple line job, to me. One trick is to use the diff(isnan(A)) to find the boundaries of NaN groups and one more 'diff' to get the length of each group. Then a loop might be used afterward. Think about it (since it is a homework ;) ) a bit. If no success, I'll give the answer.

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Image Analyst
Image Analyst 2013-12-7
编辑：Image Analyst 2013-12-7
Really easy if you have the Image Processing Toolbox. Do you have that?
measurements = regionprops(isnan(vector), 'PixelIdx');
% just 2 or 3 lines more and you've got it.
By the way, you shoudl have tagged it as homework - I did this for you this time.

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