??? Error using ==> inline.subsref at 14 Not enough inputs to inline function.

5 次查看（过去 30 天）
Lionheart
Lionheart 2013-12-7
评论： Lionheart 2013-12-8
Hi everyone,
I'm trying to make a program that finds the roots of a function using the Secant method for a class project. In class we only use very simple Matlab commands so most of the stuff I found online was way over-complicated for me to understand and use.
So what's happening is I'm getting an error:
??? Error using ==> inline.subsref at 14
Not enough inputs to inline function.
Error in ==> secante at 9 z=b-((fx(b)*(b-a))/(fx(b)-fx(a)));
when running secante(0,2,0.000001) for the function (e^(-0.5*x))*(cos(3*x))-e^(-x)
If anyone can help me understand why this is happening and check if I'm making any other mistakes it would be deeply appreciated. Here's my code:
function R = secante(a,b,erro)
f=input('Inserir f(x)= ','s');
fx = inline(f);
e=(abs(b-a))/(abs(b));
n=3;
R(1)=a;
R(2)=b;
while (erro<e)
z=b-((fx(b)*(b-a))/(fx(b)-fx(a)));
a=b;
b=z;
e=((abs(b-a))/(abs(b)));
R(n)=z;
n=n+1;
end

请先登录，再回答此问题。

采纳的回答

Walter Roberson
Walter Roberson 2013-12-7
MATLAB does not know the constant "e" and so thinks it is a variable. The user needs to enter
exp(-0.5*x)*cos(3*x)-exp(-x)
  1 个评论
Lionheart
Lionheart 2013-12-8
You're absolutely right! I was messing with my code for 3 hours and after all it was the fuction that was wrong. Thanks!

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Scope Variables and Generate Names 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by