Hey
The code you provided seems to have some syntax errors. Additionally, the use of the inline function is not recommended as it has been removed in recent versions of MATLAB.
Instead, you can define your function using anonymous function syntax. Here's an updated version of your code:
d = input('Please enter a function f(x): ');
f = @(x) eval(d);
x0 = input('Please give an initial guess of x0: ');
x1 = input('Please give an initial guess of x1: ');
x2 = input('Please give an initial guess of x2: ');
signum = input('Please enter the prespecified error: ');
i = 1;
x(i) = (f(x0)*(x1^2-x2^2) + f(x1)*(x2^2-x0^2) + f(x2)*(x0^2-x1^2)) / (2*f(x0)*(x1-x2) + 2*f(x1)*(x2-x0) + 2*f(x2)*(x0-x1));
error(i) = 9999;
es = 0.5 * 10^(2-signum);
while error(i) >= es
x(i+1) = (f(x0)*(x1^2-x2^2) + f(x1)*(x2^2-x0^2) + f(x2)*(x0^2-x1^2)) / (2*f(x0)*(x1-x2) + 2*f(x1)*(x2-x0) + 2*f(x2)*(x0-x1));
a = x(i+1);
if f(a) > f(x0)
if f(a) > f(x2)
x0 = x1;
x1 = x(i+1);
x(i+1) = (f(x0)*(x1^2-x2^2) + f(x1)*(x2^2-x0^2) + f(x2)*(x0^2-x1^2)) / (2*f(x0)*(x1-x2) + 2*f(x1)*(x2-x0) + 2*f(x2)*(x0-x1));
elseif f(a) < f(x2)
x2 = x1;
x1 = x(i+1);
end
end
error(i+1) = abs(((x(i+1)-x(i))/x(i+1)) * 100);
i = i + 1;
end
This code should now run without any syntax errors. However, please note that the quadratic interpolation algorithm you are using may not always converge or produce accurate results. It is recommended to use more robust optimization algorithms provided by MATLAB's Optimization Toolbox for such tasks.
