Using nested loops to solve kronecker product
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dear all, my question is how do solve kronecker's product of a 10x10 matrix or any matrix size using nested loops rather than the conventional Kron function.
for eg,
aa=round(rand(10,10)*10-5)
bb=round(rand(10,10)*20-10)
what do i write in the script to solve the multiplication of aa*bb using kroneckers rule.
thanks!
采纳的回答
you can do it as follows(if you have square matrices of same size):
A = round(rand(10,10)*10-5);
B = round(rand(10,10)*20-10);
for i = 1:size(A, 1)
for j = 1:size(A, 2)
AB{i, j} = A(i, j) * B;
end
end
AB = cell2mat(AB);
disp(AB)
Good luck!
4 个评论
Wei Hern
2013-12-8
Try this code:
A = round(rand(3)*10-5);
B = round(rand(3)*20-10);
for i = 1:size(A, 1)
for j = 1:size(A, 2)
AB{i, j} = A(i, j) * B;
end
end
AB = cell2mat(AB);
disp(AB)
and its answer is a 9x9 matrix which is a full matrix. Did you try it? AB is the full matrix
Wei Hern
2013-12-9
sixwwwwww
2013-12-9
you are welcome. you can accept this answer if it is helpful to you
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