Use Legend to show array and matrix

Wei
2013 12 16
2 个回答
回答已采纳
更新时间：2013 12 17
4 次查看（30 天）

0 个投票

I have one array and one matrix like A={'x' 'y' 'z'}; B=[1 2 3]. I want to make a legend as: x=1 y=2 z=3
in my plot, could anyone help me with this issue.
Thanks

请先登录，再回答此问题。

 采纳的回答

Walter Roberson
Walter Roberson 2013-12-17

0 个投票

legend( arrayfun(@(K) sprintf('%s=%d',A{K}, B(K)), 1:length(A), 'UniformOutput', false) )

4 个评论
显示 2更早的评论 隐藏 2更早的评论

Walter Roberson
Walter Roberson 2013-12-17
Alternately,
legend( strcat(A, '=', num2str(B(:)) ) )
Wei
Wei 2013-12-17
Thanks guys! I can have one legend now... But actually I just have x=1 without other two legends. Do you know how to modify?
Thanks
Wei
Wei 2013-12-17
It said: Warning: Ignoring extra legend entries.
Walter Roberson
Walter Roberson 2013-12-17
You can only have one legend entry per plotted item (e.g., one per line).
How are you doing your plotting, and what are the size() of the matrices you are plotting ?

请先登录，再进行评论。

更多回答（1 个）

Honglei Chen
Honglei Chen 2013-12-16

0 个投票

You can do this:
plot(rand(10,3))
legend(cellfun(@(x,y)sprintf('%s=%s',x,y),A,B,'UniformOutput',false))

8 个评论
显示 6更早的评论 隐藏 6更早的评论

Wei
Wei 2013-12-16
Thanks for your reply. I am sorry I just modified my question and could you please take look at it again?
Thanks
Azzi Abdelmalek
Azzi Abdelmalek 2013-12-16
Why have you changed your question?
Wei
Wei 2013-12-16
I made some change of my code...
Honglei Chen
Honglei Chen 2013-12-16
Your B now contains numbers, replace the second %s in my code to %d if they are integers
Wei
Wei 2013-12-16
It always give me this: Error using cellfun Input #2 expected to be a cell array, was double instead.
Honglei Chen
Honglei Chen 2013-12-17
You change the second one to a regular array, you can use Walter's code below
Wei
Wei 2013-12-17
Thanks a lot! I got the legend but there is only x=1 without other two.
Wei
Wei 2013-12-17
It said: Warning: Ignoring extra legend entries.

请先登录，再进行评论。

类别

在 帮助中心 和 File Exchange 中查找有关 Legend 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by