Sort columns by maximum value?

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Seth
Seth 2013-12-17
评论： Andrei Bobrov 2013-12-19
Having trouble with this one, how do I sort columns by the maximum value contained within them (must be a single line command)?
For example I have the following matrix:
5 -2 3
-10 6 2
0 0 1
The correct output should be:
3 5 -2
2 -10 6
1 0 0
I have narrowed it down to involving the max(x) command which returns the list of maximal values for each column as such:
5 6 3
But how can I then number these values in ascending order without first sorting them? e.g:
2 3 1
If I could do that then it would be simple to reorder from there. Again this problem seems easy using temporary variables but I have to do it as a single line. Any help appreciated.

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回答（4 个）

Azzi Abdelmalek
Azzi Abdelmalek 2013-12-18
编辑：Azzi Abdelmalek 2013-12-18
We can make it simple
y=x(:,sortrows([max(x);1:size(x,2)]',1)*[0;1])
Sean de Wolski
Sean de Wolski 2013-12-17
编辑：Sean de Wolski 2013-12-17
x = [5 -2 3
-10 6 2
0 0 1]
[~,idx] = sort(max(x));
y = x(:,idx)
  1 个评论
Sean de Wolski
Sean de Wolski 2013-12-17
编辑：Sean de Wolski 2013-12-17
Personally, I would never recommend doing this operation in a single line because it will just obfuscate it. If you really need to, there's probably a way using arrayfun but it'll look hideous and be unreadable.
Or you could just stack them together :)
[~,idx] = sort(max(x));y = x(:,idx)

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Azzi Abdelmalek
Azzi Abdelmalek 2013-12-17
x=[5 -2 3
-10 6 2
0 0 1];
y=x(:,setdiff(accumarray(max(x)',(1:size(x,2))'),0,'stable'))
Andrei Bobrov
Andrei Bobrov 2013-12-18
with subsref
y = x(:,subsref(sortrows([max(x)',(1:size(x,2))'],1),struct('type','()','subs',{{':',2}})))

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