ERROR in cubic spline interpolation

2013 12 21
1 个回答
更新时间：2013 12 21
13 次查看（30 天）

0 个投票

I have tried this code a thousand times but I get the same error always.
x = [0 0.0901 0.1803 0.2704 0.3606 0.4507 0.5408 0.6310 0.7211 0.8112 0.9014 0.9915 1.0817 1.1718 1.2619 1.3521 1.4422 1.5323 1.6225 1.7126 1.8028 1.8929 1.9830 2.0732 2.1633 2.2534 2.3436 2.4337 2.5239 2.6140 2.7041 2.7943 2.8844 2.9746 3.0647 3.1548 3.2450 3.3351 3.4252 3.5154 3.6055 3.6957 3.7858 3.8759 3.9661 4.0562 4.1463 4.2365 4.3266 4.4168];
y = [ 0 0.0008 0.0031 0.0070 0.0125 0.0195 0.0280 0.0380 0.0496 0.0627 0.0773 0.0934 0.1111 0.1303 0.1512 0.1737 0.1978 0.2236 0.2510 0.2797 0.3095 0.3396 0.3690 0.3965 0.4202 0.4382 0.4488 0.4509 0.4441 0.4292 0.4078 0.3818 0.3529 0.3227 0.2924 0.2627 0.2340 0.2066 0.1804 0.1556 0.1323 0.1104 0.0900 0.0712 0.0540 0.0385 0.0249 0.0135 0.0044 0];
z=linspace(0,1,50);
pp=spline(x,y);
yy=ppval(pp,z);
ERROR : ??? Error using ==> histc Edge vector must be monotonically non-decreasing.
Error in ==> ppval at 67 if lx, [~,index] = histc(xs,[-inf,b(2:l),inf]);
Please help !!!

请先登录，再回答此问题。

回答（1 个）

Image Analyst
Image Analyst 2013-12-21

0 个投票

I copied and pasted and had no error whatsoever:
x = [0 0.0901 0.1803 0.2704 0.3606 0.4507 0.5408 0.6310 0.7211 0.8112 0.9014 0.9915 1.0817 1.1718 1.2619 1.3521 1.4422 1.5323 1.6225 1.7126 1.8028 1.8929 1.9830 2.0732 2.1633 2.2534 2.3436 2.4337 2.5239 2.6140 2.7041 2.7943 2.8844 2.9746 3.0647 3.1548 3.2450 3.3351 3.4252 3.5154 3.6055 3.6957 3.7858 3.8759 3.9661 4.0562 4.1463 4.2365 4.3266 4.4168];
y = [ 0 0.0008 0.0031 0.0070 0.0125 0.0195 0.0280 0.0380 0.0496 0.0627 0.0773 0.0934 0.1111 0.1303 0.1512 0.1737 0.1978 0.2236 0.2510 0.2797 0.3095 0.3396 0.3690 0.3965 0.4202 0.4382 0.4488 0.4509 0.4441 0.4292 0.4078 0.3818 0.3529 0.3227 0.2924 0.2627 0.2340 0.2066 0.1804 0.1556 0.1323 0.1104 0.0900 0.0712 0.0540 0.0385 0.0249 0.0135 0.0044 0];
z=linspace(0,1,50);
pp=spline(x,y);
yy=ppval(pp,z)

类别

在 帮助中心 和 File Exchange 中查找有关 Splines 的更多信息

标签

提问:

Protyush
Protyush
2013-12-21

回答：

Image Analyst
Image Analyst
2013-12-21

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by