Creating a matrix with values that increase cyclically
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Hello,
I would like to create a matrix with two columns. The rows 1-670 would be 1,1; rows 671-1340 rows would be 1,2; rows 1341-2010 would be 1,3. And this trend would continue through the 670 rows of 1,256. After these rows, the next 670 rows would be 2,1; the next 670 rows would be 2,2; and the next 670 rows would be 2,3. So the trend is that every 670 rows, the second column increases by one. And every 670x256 rows, the first column increases by one and the second column resets at one.
Can someone please help with this? Any hints will be helpful.
Many thanks,
John
采纳的回答
Roger Stafford
2013-12-28
An alternative to that is:
m = 256;
n = 670;
t = (.5:m^2*n-.5)'/n;
M = [floor(t/m),mod(floor(t),m)]+1;
3 个评论
John Moseley
2013-12-28
Roger Stafford
2013-12-28
m1 = 238;
m2 = 256;
n = 670;
followed by either this:
M = [reshape(repmat(1:m1,n*m2,1),[],1),...
reshape(repmat(repmat(1:m2,n,1),1,m1),[],1)];
or this:
t = (.5:m1*m2*n-.5)'/n;
M = [floor(t/m2),mod(floor(t),m2)]+1;
John Moseley
2013-12-29
更多回答（1 个）
Roger Stafford
2013-12-28
M = [reshape(repmat(1:256,670*256,1),[],1),...
reshape(repmat(repmat(1:256,670,1),1,256),[],1)];
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