using fprintf to print same length values

How can I use fprintf to print values with the same length (the number of digits after the pointer is changing based on the number of digits before the pointer)?
0.00000000
30.0000248
360.000305

回答(2 个)

b=360.000305
m=9 % fixed length
out=sprintf('%9.9f',b)
ii=numel(strfind(out,'.'))
out=out(1:m+ii)

8 个评论

Never mind. I figured it out and corrected it:
b=[0.00000000
30.0000248
360.000305
12345.678]
m=9; % fixed length
for k = 1 : length(b)
out=sprintf('%9.9f',b(k));
ii=numel(strfind(out,'.'));
out=out(1:m+ii);
fprintf('%s\n', out);
end
Nice clever solution.
Azzi:
I would appreciate it if you finalize the answer and then I will accept this answer.
Ronaldo, Analyst has corrected the answer, in my answer a should be out. Look at edited answer
Azzi, This looks more organized. Please replace it with the current one.
b=[0.00000000
30.0000248
360.000305
12345.678]
m=9; % fixed length
for k = 1 : length(b)
out=sprintf('%9.9f',b(k));
ii=numel(strfind(out,'.'));
out=out(1:m+ii);
fprintf('%s\n', out);
end
This works fine, what is the problem?
Please add the following line (for the sake of completeness). I will accept the answer. Thanks for your great help.
fprintf('%s\n', out);
Ronaldo, I am not adding anything.

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b=360.000305
m=9 % fixed length
out=sprintf('%9.9f',b)
ii=numel(strfind(out,'.'))
out=out(1:m+ii)
% Azzi's got no time for correctness
fprintf('%s\n', out)

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提问:

2013-12-30

编辑:

2017-9-1

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