store values from a loop in a vector

2014 1 5
1 个回答
更新时间：2014 1 6
4 次查看（30 天）

0 个投票

Hi,
I have a for loop that calculates "n" values for each file. Meaning n values are calculated for file 1 and then a different n values are calculated for file 2 etc.. I just want to form arrays that contains the ith value from each of the n value. Meaning [1a, 1b,...] then [2a, 2b,...]...[na, nb,...] How would I do that?

请先登录，再回答此问题。

回答（1 个）

Azzi Abdelmalek
Azzi Abdelmalek 2014-1-5

0 个投票

Just creat a matrix nxm

6 个评论
显示 4更早的评论 隐藏 4更早的评论

anna
anna 2014-1-5
编辑：Azzi Abdelmalek 2014-1-5
Yes, but how would I assign it to n vectors instead of having a matrix. A shortened version looks something like this:
for k = 1:length(xlFiles)
col1=data(:,14);
col2=data(:,17);
j=length(col2);
for i=1:j-1
y=col1(i+1)-col1(i);
x=col2(i+1)-col2(i);
ratio = atand(y/x);
vecC(k,:)=cosd(ratio)
end
end
This is what I put for vecC but I really want vecC to be 1xk vectors of the ith "ratio" from each file.
Azzi Abdelmalek
Azzi Abdelmalek 2014-1-5
Maybe you want to change vecC(k,:)=cosd(ratio) to
vecC(k,i)=cosd(ratio)
anna
anna 2014-1-5
yeah I did that before...putting vecC(k,i)=cosd(ratio) but then it seems to repeat it n times for each file...giving n vecC arrays for each file
Azzi Abdelmalek
Azzi Abdelmalek 2014-1-5
But you have to read the data from each file, this does not appear in your code
anna
anna 2014-1-6
yes, sorry, i shortened it but there is a part where I read each file with the loop with k indices. xLfiles=dir(myFilePattern)
Azzi Abdelmalek
Azzi Abdelmalek 2014-1-6
编辑：Azzi Abdelmalek 2014-1-6
for k = 1:length(xlFiles)
%read data from files
y=diff(data(:,14)');
x=diff(data(:,17)');
ratio = atand(y./x);
vecC(k,:)=cosd(ratio)
end

请先登录，再进行评论。

类别

在 帮助中心 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by