How to delete a particular array and again in the next step create it as a new array in a for loop

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Gova ReDDy 2014-1-14

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https://ww2.mathworks.cn/matlabcentral/answers/112341-how-to-delete-a-particular-array-and-again-in-the-next-step-create-it-as-a-new-array-in-a-for-loop

评论： Gova ReDDy 2014-1-14

Hello,

I am using an array to save the values that are greater than a threshold from a particualr set of values in a for loop.

Can I know how to delete the previous array values and size.And in the next step I want to create it as new array with new size and intialising it to zeros for each iteration of for loop.

Thanks.

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Gova ReDDy 2014-1-14

编辑：Gova ReDDy 2014-1-14

在 MATLAB Online 中打开

Here it is

 for i=1:500:length(full_signal)-6000
   x1=full_signal(1,i:i+499);
          input(1,i:i+499)=full_signal(1,i:i+499);
          nonZeroElements = x1 > 0.02; 
          diffPattern = diff(nonZeroElements); 
          humpStarts = strfind(diffPattern, [1, 0]);
          if (length(humpStarts)==2)              
              needed{a}(1,1:length(next))=next(1,1:length(next));
              needed{a}(1,length(next)+1:(length(next)+humpStarts(1)))=x1(1,1:humpStarts(1));
              a=a+1;    
              needed{a}(1,1:(humpStarts(2)-humpStarts(1)))=x1(1,humpStarts(1)+1:humpStarts(2));
              a=a+1;
   %---Here I want to delete the prvious array next and want to create it as snew---%
              next(1,1:length(x1)-humpStarts(2))=x1(1,humpStarts(2)+1:length(x1));
          elseif(length(humpStarts)==1)
              needed{a}(1,1:length(next))=next(1,1:length(next));
              needed{a}(1,length(next)+1:(length(next)+humpStarts(1)))=x1(1,1:humpStarts(1));
              a=a+1;     
   %---Here I want to delete the prvious array next and want to create it as snew---%        
              next(1,1:length(x1)-(humpStarts(1)))=x1(1,humpStarts(1)+1:length(x1)); 
          else 
   %---Here I want to delete the prvious array next and want to create it as snew---%
              next(1,1:length(x1))=x1(1,1:length(x1));   
          end;  
end;

Azzi Abdelmalek 2014-1-14

I mean give a short example and explain what you want to achieve

Gova ReDDy 2014-1-14

在 MATLAB Online 中打开

Assume if the size of next array is 1x500 then the values will be stored into needed{1}

   length(humpStarts)==1)
                needed{a}(1,1:length(next))=next(1,1:length(next));

in the next step here it will store the remaining values from 501 to index at which hump occurs

needed{a}(1,length(next)+1:(length(next)+humpStarts(1)))=x1(1,1:humpStarts(1));
a=a+1;

In the next step if the values from humpStarts(1)+1:length(x1) are 15 then the nextarray here is replacing its first 15 values with the 15 values from x1 and leaving the remaining previous values from 15+1 to the length of previous next array.

next(1,1:length(x1)-(humpStarts(1)))=x1(1,humpStarts(1)+1:length(x1));

But here in the last step I just want to save the current 15 values from x1 in the next array making its size limited to only 15 and I don't even want to have zero values from the next 15 values(I mean I want to have the size of next array that can only fit the remaning values from humpStarts(1)+1:length(x1) .

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