Changing size vector. Avoiding a loop

2 次查看（过去 30 天）

Javier 2014-1-14

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/112390-changing-size-vector-avoiding-a-loop

评论： Amit 2014-1-14

I have a problem that is taking hours to be solved and I am trying to gain efficience in order to make it faster. Basically, I had three loops and I was able to replace two of them by using element by element operations, but I don't know how to get ride of the last loop because I need a scalar and a vector that change in every iteration.

Do you know if there is a way to solve this problem more efficiently? I know I am not very clear but I don't know how to explain the problem better.

My code looks something like this:

T=[1:1:10];
for j=1:length(T)
    s=0.001:0.001:T(j);
    x1=0:0.5:5;
    x1=x1';
    omega=zeros(length(x1),length(s));
    omega=repmat(s,length(x1),1);
    x=zeros(length(x1),length(s));
    x=repmat(x1,1,length(s));
    omega=exp(-x.^2./2./(T(j)-omega))./((omega.*(T(j)-omega)).^(3/2));
    omega=flipud(cumsum(flipud(omega')))'*0.0005;
end

Well, I'll be very glad if someone can help me a little with this. Thank you in advance Javier

3 个评论
显示 1更早的评论隐藏 1更早的评论

dpb 2014-1-14

在 MATLAB Online 中打开

Plus, get rid of the extra rearrangements -- instead of

x=0:N;
x=x'

write

x=0:N';

from the git-go. I didn't try to read the code closely enough to try to discern the intent but I'd think you could generate the vectors in the proper order to begin with as well to get rid of the flipud as well. That seems likely to be unnecessary with forethought.

Amit 2014-1-14

Moreover, initialization in the loop is not going to make any difference. You can remove zeros initialization in the loop.

Also, can you post the equation you are trying to solve? That might give some ideas on how to solve this (cause x^2/2/(T-omega) seems a bit odd (double division?).

Another suggestion - profiler . That might come in handy for slow code.

请先登录，再进行评论。

请先登录，再回答此问题。