please identify my mistake

2014 1 16
2 个回答
更新时间：2021 8 20
4 次查看（30 天）

0 个投票

l1=1;
for j=1:108
for t=2:108
if j<t
d2(l1,:)=c4*0;
else if j>=t
d2(l1,:)=c4*m1.a(1,2)^(j-1);
l1=l1+1;
end
end
end
end

4 个评论
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Walter Roberson
Walter Roberson 2014-1-16
What error are you observing? Are you getting an error message, or is the result different than what you are expecting ?
arfa maqsood
arfa maqsood 2014-1-16
I am getting 'dimension mismatch' error
Walter Roberson
Walter Roberson 2014-1-16
Which line is the error occurring on?
Are you initializing d2 before the loop, or are you having d2 implicitly expanded as the loop runs?
arfa maqsood
arfa maqsood 2014-1-16
I initialize d2 by giving l1=1 before the loop. m1.a(1,2) is a scalar quantity stored by applying a time series model AR(1). I am writing a loop that is conditional too. c4 is a column vector of order 40018*1. I have to apply formula to first group of 374 observations in c4 and then to second group of 374 observations and so on. Basically it should generate a matrix of order 40018*108.

回答（2 个）

Azzi Abdelmalek
Azzi Abdelmalek 2014-1-16

0 个投票

  • instead of .
d2(l1,:)=c4*m1*a(1,2)^(j-1)

1 个评论
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arfa maqsood
arfa maqsood 2014-1-16
m1.a(1,2) is a scalar quantity stored by applying a time series model AR(1). I am writing a loop that is conditional too. c4 is a column vector of some order. I have to apply formula to first group of observations in c4 and then to second group and so on.
Walter Roberson
Walter Roberson 2014-1-16

0 个投票

In the case j < t, why are you not incrementing l1 ?

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