convert class 'char' to class 'logical' , How?
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I have some binary bits in a string of class 'char':
b= 10001010101010101000000111110000111
I wish to covert class of 'b' from 'char' to 'logical'.
When i use str2num function, it considers all the bits as a single number and returns me
str2num(b)
ans =
1.0001e+034
Which i don't want. i want b as a logical array.
Kindly Help.
采纳的回答
Mischa Kim
2014-1-17
9 个投票
Try
b_bin = logical(b(:)'-'0')
7 个评论
Furqan Haider
2014-1-17
Michael Pugh
2020-6-24
This works but I can't really understand it. Clever though.
Linden Yuan
2021-4-11
@Michael Pugh Another solution that works is
b_bin = logical(b'-'0')
The -'0' part tells Matlab to subtract the ASCII value of 0, namely 48, from the ASCII values of b', which will be 48 or 49 depending on whether the entry is 0 or 1. In the end, b'-'0' will be a vector of doubles, and we convert that to a logical vector. (See also https://stackoverflow.com/questions/20032413/matlab-string-vector-character-subtraction .)
Saravanakumar Chandrasekaran
2021-5-28
b= '10001010101010101000000111110000111'
b_bin = logical(b(:)'-'0')
How to convert back the b_bin to b
James Tursa
2021-5-28
b = char(b_bin+'0')
"Why this is not indicated in the Documentation for 'logical' function?"
It already is: it states at the very top "logical(A) converts A into an array of logical values. Any nonzero element of A is converted to logical 1 (true) and zeros are converted to logical 0 (false)", which is exactly what happens here.
Of course the LOGICAL documentation cannot cover every possible way that you might create the input array (you did not consider that there are many many many many other ways of creating the input array and there is nothing special about this particular way so your proposal would mean including basically a very large subset of the entire MATLAB documentation on every single MATLAB documentation page... such documentation would be truly very large and very difficult to find anything in).
更多回答（2 个）
William Prophet
2016-11-11
If you want to convert the character array to a logical one, just compare the entire array character by character. So if you have '001011' and you want to return [0 0 1 0 1 1], just do
'001011' == '1'
And then every character in the array is compared to '1'.
Andreas Goser
2014-1-17
1 个投票
Logical can only hold 0 or 1, so 10001010101010101000000111110000111 is not possible. Maybe you want binary numbers?
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