Why do I get NAN?

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Yasmin Tamimi
Yasmin Tamimi 2014-1-19
评论： Dheeraja Karthikeyan 2020-4-25
Hey everyone,
I'm running this equation
hMphi(1) = - (dd_Anis(1) * ddu_acos(1) * du_dMphi(1))/(C2*sin(Mtheta(1)))- ((Is*P_hbar/(2*P_Q*g*C2))*((ephix(1)*Ffx(1))+(ephiy(1)*Ffy(1))))- Ms*(Ny-Nx)*sin(Mtheta(1))*sin(2*Mphi(1))+ (Happy*cos(Mphi(1)) - Happx*sin(Mphi(1))) ;
in a loop and a certain point the value of this vector becomes a NAN?! Can Anyone tell me why is this happening? I' dividing by a sin, so I thought that maybe the problem is from it, but I printed the values of it I didn't get Inf.
Thanks

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采纳的回答

Roger Stafford
Roger Stafford 2014-1-19
Any of these arithmetic operations will produce a NaN: zero/zero, zero*infinity, infinity/infinity, infinity-infinity. For example, if any of the three quantities, dd_Anis, ddu_acos, or du_dMph were to become zero at the same time that sin(Mtheta) is zero, that would produce a NaN. You should make a test on hMphi each time it is computed and arrange to stop if a NaN is detected so you can check all the values that go into your equation at that point.

更多回答（2 个）

Jan
Jan 2014-1-19
You can stop the code automatically, when the NaN appears:
dbstop if naninf
Then inspect the local variables and evaluate the different parts of the equation in the command window until you find the reason for the NaN.
  1 个评论
Dheeraja Karthikeyan
Dheeraja Karthikeyan 2020-4-25
Thanks a lot for this! You were a blessing in disguise!

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Anna
Anna 2014-1-19
Have you tried to isolate the part of the equation where the fault is at? Debug the equation in the loop iteration before the equation turns into a NaN.

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