unable to plot graph as well as form a table as it is taking only last value of the loop,plz help me in this particular matter as i ve my submission on coming friday

Question

ellora 2014-1-21

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/113143-unable-to-plot-graph-as-well-as-form-a-table-as-it-is-taking-only-last-value-of-the-loop-plz-help-me

回答： AJ von Alt 2014-1-21

采纳的回答： AJ von Alt

在 MATLAB Online 中打开

Y1 =

7.7054

Y2 =

    9.6584
I(1)= -0.0159
 I(2)=-0.0128
 I(3)=-0.0043
  I(4)=0.4141
  I(5)=0.2673
 I(6)=-0.0043
for y=0.45:-0.05:0.25  
ud=(I(3)*exp(Y2*y)+I(4)*exp(-Y2*y)+k2)^0.5;
taub=(f*ro*ud^2)/8;
end
for y=0.25:-0.05:0
ud=(I(1)*exp(Y1*y)+(I(2)*exp(-Y1*y))+k1)^0.5;
taub=(f*ro*ud^2)/8;
end
for y=0.0:-0.05:-0.25    
ud=(I(1)*exp(-Y1*y)+(I(2)*exp(Y1*y))+k1)^0.5;
taub=(f*ro*ud^2)/8;
end
for y=-0.25:-0.05:-0.45
ud=(I(3)*exp(-Y3*y)+I(4)*exp(Y3*y)+k2)^0.5;
taub=(f*ro*ud^2)/8;
end

table1=[y,ud]; table2=[y,taub]; fid1=fopen('depth averaged value.txt','w'); fid2=fopen('boundary shear.txt','w'); fprintf(fid1,' m m/s \n'); fprintf(fid1,'%8.2f %8.2f\n',table1); fprintf(fid2,' m N/m^2 \n'); fprintf(fid2,'%8.2f %8.2f\n',table2); fclose(fid1); fclose(fid2); plot(y,ud)

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Answer 1

AJ von Alt 2014-1-21

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/113143-unable-to-plot-graph-as-well-as-form-a-table-as-it-is-taking-only-last-value-of-the-loop-plz-help-me#answer_121652

The code for generating the table and printing it to a file is correct, but the variables y, ud, and taub are all scalars. Each iteration of each for loop overwrites the previous values of y, ud, and taub.

One way to solve this problem is to make the variables vectors and store the result of each calculation as an element of the corresponding vector.

See the indexing documentation for information on how to access data in vectors and matrices and the for loop documentation for an example of how to store and retrieve data in a vector using a for loop.