calling a dll

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Steve
Steve 2011-7-11
I wish to call my dll (simpledll)from Matlab R2007b; I have loaded the dll successfully. Then from the 'libfunctions' I get the function: "doublePtr changevar(double, doublePtr)" displayed. This looks ok to me, as all it does is inputs a value (double) & returns a value (double).
I tried calling it using the following: in1=2; [out1]=callib('simpledll','changevar',in1);
But I get the following error on the calling line: "Undefined function or method 'callib' for input arguments of type 'char'."
What does this mean; have I got the format for calling the dll wrong; what should I have put?

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采纳的回答

Friedrich
Friedrich 2011-7-11
Hi,
this be because calllib is written with three l instead of two like you did.
  2 个评论
Steve
Steve 2011-7-11
Yes you are correct;MatLab did not highlight the typo error. I have corrected this but now get the error message "Error using==> calllib
No method with matching signature". Any ideas what this means?
Kaustubha Govind
Kaustubha Govind 2011-7-11
doublePtr changevar(double, doublePtr)
this seems to indicate that the function needs two inputs, but you are only providing one.

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更多回答（1 个）

Steve
Steve 2011-7-11
Yes you are correct;MatLab did not highlight the typo error. I have corrected this but now get the error message "Error using==> calllib No method with matching signature". Any ideas what this means?
  3 个评论
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Steve
Steve 2011-9-27
The dll (simpledll)has a function called 'changevar' with one input 'in1' and one output 'out1'. So have I got the MatLab format wrong: [out1]= calllib('simpledll','changevar',in1)?
Kaustubha Govind
Kaustubha Govind 2011-9-27
You said that libfunctions lists the function as "doublePtr changevar(double, doublePtr)" - this indicates that the function has 2 inputs. What is the corresponding signature for the function with one input?

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