How to create user defined function in matlab?

2014 1 22
2 个回答
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更新时间：2014 1 23
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0 个投票

I have use below set of code frequently. So i have to make user defined function
below is my frequently used code:-
x=xvalue;
y=yvalue;
for j=1:3;
red(j)=RGB(y,x,j);
end
shape.color=red;

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Azzi Abdelmalek
Azzi Abdelmalek 2014-1-22
Can you explain what are the argument (inputs and outputs) of your function?
saravanakumar D
saravanakumar D 2014-1-22
编辑：saravanakumar D 2014-1-22
input is x and y values
output is pixel color value -->shape.color= [242 0 12]

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Image Analyst
Image Analyst 2014-1-22
编辑：Image Analyst 2014-1-22

0 个投票

I think this is the minimum necessary:
function shape = myFunction(RGB, xvalue, yvalue, i)
x=xvalue;
y=yvalue;
for j=1:3;
red(j)=RGB(y,x,j);
end
shape(i).color=red;
Optionally, x, y, and red could also be outputs, and shape could also be an input. Be aware that the "red" variable actually contains the red, green, and blue values from the pixel at (y, x).

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saravanakumar D
saravanakumar D 2014-1-22
编辑：saravanakumar D 2014-1-22
You didn't store the result value in to variable shape, then how it gives output?
saravanakumar D
saravanakumar D 2014-1-22
编辑：saravanakumar D 2014-1-22
Is below code is correct? And i don't need i, so i neglect
function shape = myFunction(RGB, xvalue, yvalue)
x=xvalue;
y=yvalue;
for j=1:3;
red(j)=RGB(y,x,j);
end
shape.color=red;
shape=shape.color;
Walter Roberson
Walter Roberson 2014-1-22
No, the last line is wrong. You cannot have two assignments in a single expression.
Walter Roberson
Walter Roberson 2014-1-23
shape.color=red;
creates "shape" as a structure with a field "color" that it sets to the content of "red". Then your statement
shape=shape.color
overwrites "shape" with the contents of the field "color", into which you had written the content of "red". The net effect of your code is as the same as if you had changed those last two lines to
shape = red;
Image Analyst
Image Analyst 2014-1-23
Do you want a structure or not? If there is only one field, then I see no reason at all to use a structure. Just use a simple variable.

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更多回答（1 个）

Walter Roberson
Walter Roberson 2014-1-22

0 个投票

function shape = myFunction(RGB, xvalue, yvalue, i)
shape(i).color = squeeze(RGB(xvalue, yvalue, :));

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saravanakumar D
saravanakumar D 2014-1-22
which is output variable shape or shape(i).color?
Walter Roberson
Walter Roberson 2014-1-22
The output variable is "shape", as listed in the function header. The "shape" that is output will be a structure array with a single field "color", with the "i"th element of the structure array populated with meaningful data and the rest of the shape(K).color will be the empty array []

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