its not taking the values of y when y value is ranging from 0.25 to 0.45 with an interval of 0.05,but it is able to take the value when y value is constant. and its coming in some matrix but with constant values.

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ellora 2014-1-23

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https://ww2.mathworks.cn/matlabcentral/answers/113391-its-not-taking-the-values-of-y-when-y-value-is-ranging-from-0-25-to-0-45-with-an-interval-of-0-05-bu

评论： ellora 2014-1-26

Y1 =    7.7054
Y2 = 9.6584   
I(3)= -0.0043
I(4)=0.4141
n=4 ;
m=2; 
y=0.25:0.05:0.45;
      for j=1:m
          for i=1:n
              if (j==1)
          ud(i+1,1)=y;
          taub(i+1,1)=y;
          ud(i+1,2)=(I(3)*exp(Y2*y)+I(4)*exp(-Y2*y)+k2)^0.5;
          taub(i+1,2)=(f*ro*ud(i+1,2)^2)/8;
              end
      end
      end
  ud
  taub
  plot(ud(i,1),ud(i,2))

sir here y will be my first column and ud will be my second column,bt ud is dependent on y,y is varying from 0.25 to 0.45 by having an interval of 0.05. here i just want to change the value of y in each iteration.

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ellora 2014-1-25

table does nt mean taub,and i said 'find' that means i want to ve my data in a tabular format. that too the table should contain 2 columns,one for the value of y and the 2nd column for ud.there is nothing related to taub(its a different variable).

ellora 2014-1-26