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Help with compiling Matrix & Loop Function Please

1 次查看(过去 30 天)
I have split the below nodes into a number of sub elements
node1 (0 0) node2 (0 6) node3 (6 6) node4 (6 0)
element1 nodes (1 2) element2 nodes (2 3) element3 nodes (3 4) element4 nodes (2 4)
>> sub_ele_nodes
sub_ele_nodes(:,:,1) =
0 0
0 1.5000
0 3.0000
0 4.5000
0 6.0000
sub_ele_nodes(:,:,2) =
0 6.0000
1.5000 6.0000
3.0000 6.0000
4.5000 6.0000
6.0000 6.0000
sub_ele_nodes(:,:,3) =
6.0000 6.0000
6.0000 4.5000
6.0000 3.0000
6.0000 1.5000
6.0000 0
sub_ele_nodes(:,:,4) =
0 6.0000
1.5000 4.5000
3.0000 3.0000
4.5000 1.5000
6.0000 0
I now wish to compile the above in one matrix, but I may have more elements than 4 so therefore I guess I need a loop. I also do not want any of the nodes repeating each other. Result should be:
>> nodes
0 0
0 1.5000
0 3.0000
0 4.5000
0 6.0000
1.5000 6.0000
3.0000 6.0000
4.5000 6.0000
6.0000 6.0000
6.0000 4.5000
6.0000 3.0000
6.0000 1.5000
6.0000 0
1.5000 4.5000
3.0000 3.0000
4.5000 1.5000
Please can someone help?

回答(2 个)

Amit
Amit 2014-1-25
编辑:Amit 2014-1-25
nodes = permute(sub_ele_nodes,[1 3 2]);
nodes = reshape(nodes,[],size(sub_ele_nodes,2),1);
nodes = unique(nodes,'rows','stable');
  2 个评论
Peter cullen
Peter cullen 2014-1-25
Hi Amit,
I put this into my code but all it is returning is 0 0. Im new to Matlab, and I recon I am doing something very simple wrong. Any Ideas? Thank you
Amit
Amit 2014-1-25
Before posting this, I tried it against the sub_ele_nodes that you provided in the question. And got exactly what you wanted.
I'd say before trying the code, try one time just typing
sub_ele_nodes
and checking if the matrix is still same.

Andrei Bobrov
Andrei Bobrov 2014-1-25
a = num2cell(sub_ele_nodes,[1 2]);
[aa,b] = unique(cat(1,a{:}),'first','rows');
[~,ii] = sort(b);
out=aa(ii,:);
  1 个评论
Peter cullen
Peter cullen 2014-1-25
Hi Andrei,
Thank you, I inputted this into my code & it returned 0 0. Im new to matlab so can you tell me if I am doing something incorrectly.
Peter

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