Help with compiling Matrix & Loop Function Please
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I have split the below nodes into a number of sub elements
node1 (0 0) node2 (0 6) node3 (6 6) node4 (6 0)
element1 nodes (1 2) element2 nodes (2 3) element3 nodes (3 4) element4 nodes (2 4)
>> sub_ele_nodes
sub_ele_nodes(:,:,1) =
0 0
0 1.5000
0 3.0000
0 4.5000
0 6.0000
sub_ele_nodes(:,:,2) =
0 6.0000
1.5000 6.0000
3.0000 6.0000
4.5000 6.0000
6.0000 6.0000
sub_ele_nodes(:,:,3) =
6.0000 6.0000
6.0000 4.5000
6.0000 3.0000
6.0000 1.5000
6.0000 0
sub_ele_nodes(:,:,4) =
0 6.0000
1.5000 4.5000
3.0000 3.0000
4.5000 1.5000
6.0000 0
I now wish to compile the above in one matrix, but I may have more elements than 4 so therefore I guess I need a loop. I also do not want any of the nodes repeating each other. Result should be:
>> nodes
0 0
0 1.5000
0 3.0000
0 4.5000
0 6.0000
1.5000 6.0000
3.0000 6.0000
4.5000 6.0000
6.0000 6.0000
6.0000 4.5000
6.0000 3.0000
6.0000 1.5000
6.0000 0
1.5000 4.5000
3.0000 3.0000
4.5000 1.5000
Please can someone help?
0 个评论
回答（2 个）
nodes = permute(sub_ele_nodes,[1 3 2]);
nodes = reshape(nodes,[],size(sub_ele_nodes,2),1);
nodes = unique(nodes,'rows','stable');
2 个评论
Peter cullen
2014-1-25
Amit
2014-1-25
Before posting this, I tried it against the sub_ele_nodes that you provided in the question. And got exactly what you wanted.
I'd say before trying the code, try one time just typing
sub_ele_nodes
and checking if the matrix is still same.
Andrei Bobrov
2014-1-25
a = num2cell(sub_ele_nodes,[1 2]);
[aa,b] = unique(cat(1,a{:}),'first','rows');
[~,ii] = sort(b);
out=aa(ii,:);
1 个评论
Peter cullen
2014-1-25
此问题已关闭。
2014-1-25
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2021-8-20
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