How to access randomly selected index in nested structures

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Darina
Darina 2014-1-28
评论： Darina 2014-2-9
I want to access intexes that are into a structure that are nested within another structure. I have this code working through every ith element, and I want to add to the code randomly selected values j. In my case j is from 1 to 365 day of the year.
for i=1:n
fileName=structName(i).nestedStructName(j).name
end
Any ideas?
Darina

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采纳的回答

Amit
Amit 2014-1-28
Try something like this:
for i=1:n
X = fieldnames(structName);
n = length(X);
fileName=structName(i).(X{randi(n)}).name;
end
The issue is that your nestedStucture has multiple fields and you wanna pick one randomly.

更多回答（2 个）

Mischa Kim
Mischa Kim 2014-1-28
How about
fileName=structName(i).nestedStructName(randi(365,1)).name
Is this what you are looking for?
  7 个评论
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Darina
Darina 2014-1-28
[rS, cS] = size(allFileMin)
[rnS, cnS] = size(allFileMin(rS).demand_pattern)
the answer:
rS =
1
cS =
28
Reference to non-existent field 'demand_pattern'.
Error in Activity (line 136)
[rnS, cnS] = size(allFileMin(rS).demand_pattern)
Darina
Darina 2014-1-28
This happends because I only have nestedStructName1 to nastedStructName365 but not a single naestedStructName without index.

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Shivaputra Narke
Shivaputra Narke 2014-1-28
May this works,
for i=1:n j=1+round(364*rand(1)); fileName=structName(i).nestedStructName(j).name end

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