Define a variable via inputdlg?
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I would like a variable to be assigned via a user prompt. For example, consider the following command:
row = inputdlg('Insert row number.');
When a user inputs 1 in the popup box, the value of the variable "row" is not recognized as a number or a string, but as a '1', with ticks surrounding it.
Is there a way to have a variable defined as a number or a string from a popup box?
Thank you!
采纳的回答
Amit
2014-1-30
row = inputdlg('Insert row number.');
row = str2num(row{:});
更多回答（1 个）
David Sanchez
2014-1-30
You can do it in a single line and use str2double which is faster than str2num:
row = str2double( inputdlg('Insert row number.') );
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