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Can you help me solving that?

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Rengin
Rengin 2014-1-30
编辑： Walter Roberson 2014-1-30
A=[1 2 3 4 5 6 7 8 9 10]
B=[a b c d e f ]
I want to create such a matrix as a result:
C[1+a 1+b 1+c 1+d 1+e 1+f ; 2+a ... 2+f ; 3+a... 3+f; ......;10+a...10+f]
A is 1x10 and B is 1x6 sized matrices. C is 10x6 sized matrix.
Thank you for your help!

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采纳的回答

Mischa Kim
Mischa Kim 2014-1-30
How about:
A = [1 2 3 4 5 6];
b = [1 2 3];
C = zeros(size(A'*b));
for ii = 1:length(A)
C(ii,:) = b + A(ii);
end

更多回答（2 个）

Iain
Iain 2014-1-30
编辑：Iain 2014-1-30
C = A * B'; % will give you a 1x1.
C = (A' * B)'; will give you a 10x6.
C = A'*B; will give you a 6 x 10.
  2 个评论
Rengin
Rengin 2014-1-30
Yes you are right but the thing is that I am getting the first element of A matrix (which is "1" ) and adding it the first row of the B matrix and getting the first row of C matrix (1+a 1+b 1+c 1+d 1+e 1+f). I am doing that procedure untill fulfill all of my rows (I have 6 rows)... I know how to multiply the matrices. My guestion is how to create a new matrix according to my specific summary rule.
Jos (10584)
Jos (10584) 2014-1-30
you mean: I have 10 rows ...

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Jos (10584)
Jos (10584) 2014-1-30
No need for an explicit loop as you can exploit the power of MatLab with BSXFUN.
% example data
A =[1 2 3 4 5 6 7 8 9 10]
B =[100 200 300 400 500]
% engine
C = bsxfun(@plus, A(:), B)

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