Can you help me solving that?

2 次查看（过去 30 天）
Rengin
Rengin 2014-1-30
编辑： Walter Roberson 2014-1-30
A=[1 2 3 4 5 6 7 8 9 10]
B=[a b c d e f ]
I want to create such a matrix as a result:
C[1+a 1+b 1+c 1+d 1+e 1+f ; 2+a ... 2+f ; 3+a... 3+f; ......;10+a...10+f]
A is 1x10 and B is 1x6 sized matrices. C is 10x6 sized matrix.
Thank you for your help!

请先登录，再回答此问题。

采纳的回答

Mischa Kim
Mischa Kim 2014-1-30
How about:
A = [1 2 3 4 5 6];
b = [1 2 3];
C = zeros(size(A'*b));
for ii = 1:length(A)
C(ii,:) = b + A(ii);
end

更多回答（2 个）

Iain
Iain 2014-1-30
编辑：Iain 2014-1-30
C = A * B'; % will give you a 1x1.
C = (A' * B)'; will give you a 10x6.
C = A'*B; will give you a 6 x 10.
  2 个评论
Rengin
Rengin 2014-1-30
Yes you are right but the thing is that I am getting the first element of A matrix (which is "1" ) and adding it the first row of the B matrix and getting the first row of C matrix (1+a 1+b 1+c 1+d 1+e 1+f). I am doing that procedure untill fulfill all of my rows (I have 6 rows)... I know how to multiply the matrices. My guestion is how to create a new matrix according to my specific summary rule.
Jos (10584)
Jos (10584) 2014-1-30
you mean: I have 10 rows ...

请先登录，再进行评论。

Jos (10584)
Jos (10584) 2014-1-30
No need for an explicit loop as you can exploit the power of MatLab with BSXFUN.
% example data
A =[1 2 3 4 5 6 7 8 9 10]
B =[100 200 300 400 500]
% engine
C = bsxfun(@plus, A(:), B)

类别

在 Help Center 和 File Exchange 中查找有关 Numerical Integration and Differential Equations 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by